maths.free › Abstract Algebra › Rings › Ring Homomorphisms and Ideals
Ring Homomorphisms and Ideals
In the study of groups, a homomorphism is a map that preserves the operation of the group. Similarly, a homomorphism between rings preserves the operations of addition and multiplication in the ring.
Ring Homomorphisms and Ideals
In the study of groups, a homomorphism is a map that preserves the operation of the group. Similarly, a homomorphism between rings preserves the operations of addition and multiplication in the ring. More specifically, if \(R\) and \(S\) are rings, then a ring homomorphism is a map \(\phi : R \rightarrow S\) satisfying \[\begin{aligned}\phi( a + b ) & = \phi( a ) + \phi(b) \\ \phi( a b ) & = \phi( a ) \phi(b)\end{aligned}\] for all \(a, b \in R\). If \(\phi : R \rightarrow S\) is a one-to-one and onto homomorphism, then \(\phi\) is called an isomorphism of rings.
The set of elements that a ring homomorphism maps to \(0\) plays a fundamental role in the theory of rings. For any ring homomorphism \(\phi : R \rightarrow S\), we define the kernel of a ring homomorphism to be the set \[\begin{aligned}\end{aligned}\].
Example
For any integer \(n\) we can define a ring homomorphism \(\phi : {\mathbb Z} \rightarrow {\mathbb Z}_n\) by \(a \mapsto a \pmod{n}\). This is indeed a ring homomorphism, since \[\begin{aligned}\phi( a + b ) & = (a + b) \pmod{n} \\ & = a \pmod{n} + b \pmod{n} \\ & = \phi( a ) + \phi(b)\end{aligned}\] and \[\begin{aligned}\phi( a b ) & = ab \pmod{n} \\ & = a \pmod{n}\cdot b \pmod{n} \\ & = \phi( a ) \phi(b)\end{aligned}\]. The kernel of the homomorphism \(\phi\) is \(n {\mathbb Z}\).
Example
Let \(C[a, b]\) be the ring of continuous real-valued functions on an interval \([a,b]\) as in . For a fixed \(\alpha \in [a, b]\), we can define a ring homomorphism \(\phi_{\alpha} : C[a, b] \rightarrow {\mathbb R}\) by \(\phi_{\alpha} (f ) = f( \alpha)\). This is a ring homomorphism since \[\begin{aligned}\phi_{\alpha}( f + g ) = (f + g)( \alpha) = f(\alpha) + g(\alpha) = \phi_{\alpha}( f ) + \phi_{\alpha}(g ) \\ \phi_{\alpha}( f g ) = (f g)( \alpha) = f(\alpha) g(\alpha) = \phi_{\alpha}( f ) \phi_{\alpha}(g )\end{aligned}\]. Ring homomorphisms of the type \(\phi_{\alpha}\) are called evaluation homomorphisms.
In the next proposition we will examine some fundamental properties of ring homomorphisms. The proof of the proposition is left as an exercise.
Example
Every ring \(R\) has at least two ideals, \(\{ 0 \}\) and \(R\). These ideals are called the trivial ideals.
Let \(R\) be a ring with identity and suppose that \(I\) is an ideal in \(R\) such that \(1\) is in \(I\). Since for any \(r \in R\), \(r1 = r \in I\) by the definition of an ideal, \(I = R\).
Condensed: the full section is in Judson, Abstract Algebra: Theory and Applications.
Now you Nijedan kalkulator ne slaže ovaj, ali komadiće su komputentni. Pokušajte jedan ispod, ili upišite vlastiti.
Besplatan račun dodaje bilješke na svakoj lekciji, zapis onoga što ste završili, rješeni problemi na jednom mjestu, i tutor možete pitati o ovoj stranici. Sama matematika je otvorena za sve, potpisani ili ne.
Prijavi se PrijavaSimboli koji se koriste ovdje
Dodirnite bilo koji simbol za punu definiciju, sliku, i što znači svako slovo u njoj.
Pitanja koja ljudi postavljaju
What is a group, in plain words?
A set with one operation that is associative, has an identity, and lets every element be undone. Symmetries of any object form a group. That is where the idea came from.
What is the difference between a ring and a field?
A ring has addition and multiplication that behave like the integers (you cannot always divide); a field is a ring where every non-zero element has a reciprocal, like the rationals or the reals.
Dijelovi ove stranice prilagođeni su od Judson, Abstract Algebra: Theory and Applications (GFDL 1.3). Ovdje su kondenzirane i objašnjene; greške su naše.
Više u Abstract Algebra
GroupsSubgroups, cosets and Lagrange's theoremCyclic groups and permutation groupsHomomorphisms, normal subgroups and quotient groupsRings and fieldsGalois theory: why the quintic has no formula