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Polynomial Rings
Throughout this chapter we shall assume that R is a commutative ring with identity.
Polynomial Rings
Throughout this chapter we shall assume that \(R\) is a commutative ring with identity. Any expression of the form \[\begin{aligned}\end{aligned}\], where \(a_i \in R\) and \(a_n \neq 0\), is called a polynomial over \(R\) with indeterminate \(x\). The elements \(a_0, a_1, \ldots, a_n\) are called the coefficients of \(f\). The coefficient \(a_n\) is called the leading coefficient. A polynomial is called monic if the leading coefficient is \(1\). If \(n\) is the largest nonnegative number for which \(a_n \neq 0\), we say that the degree of \(f\) is \(n\) and write \(\deg f(x) = n\). \(\deg f(x)\) degree of a polynomial If no such \(n\) existsthat is, if \(f=0\) is the zero polynomialthen the degree of \(f\) is defined to be \(-\infty\). We will denote the set of all polynomials with coefficients in a ring \(R\) by \(R[x]\). \(R[x]\) ring of polynomials over a ring \(R\) Two polynomials are equal exactly when their corresponding coefficients are equal; that is, if we let \[\begin{aligned}p(x) & = a_0 + a_1 x + \cdots + a_n x^n \\ q(x) & = b_0 + b_1 x + \cdots + b_m x^m\end{aligned}\], then \(p(x) = q(x)\) if and only if \(a_i = b_i\) for all \(i \geq 0\).
To show that the set of all polynomials forms a ring, we must first define addition and multiplication. We define the sum of two polynomials as follows. Let \[\begin{aligned}p(x) & = a_0 + a_1 x + \cdots + a_n x^n \\ q(x) & = b_0 + b_1 x + \cdots + b_m x^m\end{aligned}\]. Then the sum of \(p(x)\) and \(q(x)\) is \[\begin{aligned}\end{aligned}\], where \(c_i = a_i + b_i\) for each \(i\). We define the product of \(p(x)\) and \(q(x)\) to be \[\begin{aligned}\end{aligned}\], where \[\begin{aligned}\end{aligned}\] for each \(i\). Notice that in each case some of the coefficients may be zero.
Example
Suppose that \[\begin{aligned}\end{aligned}\] and \[\begin{aligned}\end{aligned}\] are polynomials in \({\mathbb Z}[x]\). If the coefficient of some term in a polynomial is zero, then we usually just omit that term. In this case we would write \(p(x) = 3 + 2 x^3\) and \(q(x) = 2 - x^2 + 4 x^4\). The sum of these two polynomials is \[\begin{aligned}\end{aligned}\]. The product, \[\begin{aligned}\end{aligned}\], can be calculated either by determining the \(c_i\)s in the definition or by simply multiplying polynomials in the same way as we have always done.
Condensed: the full section is in Judson, Abstract Algebra: Theory and Applications.
Tani ti. Asnjë kalkulator nuk e zgjidh këtë, por pjesët e saj janë të llogaritura. Provo një më poshtë, ose shkruaj tënde.
Një llogari e lirë shtohet shënime në çdo mësim, një regjistrim të asaj që ju keni përfunduar, problemet tuaja të zgjidhura në një vend, dhe një mësues që ju mund të pyesni rreth kësaj faqeje. Matematika vetë është e hapur për të gjithë, të regjistruar apo jo.
Regjistrohu HyrSimbolet e përdorura këtu
Prek çdo simbol për përkufizimin e plotë, një fotografi dhe se çfarë do të thotë çdo shkronjë në të.
Pyetja që bëjnë njerëzit
What is a group, in plain words?
A set with one operation that is associative, has an identity, and lets every element be undone. Symmetries of any object form a group. That is where the idea came from.
What is the difference between a ring and a field?
A ring has addition and multiplication that behave like the integers (you cannot always divide); a field is a ring where every non-zero element has a reciprocal, like the rationals or the reals.
Pjesa e kësaj faqeje është adaptuar nga Judson, Abstract Algebra: Theory and Applications (GFDL 1.3). E përmbledhur dhe ri-shkruar këtu; gabimet janë tona.
Më shumë në Abstract Algebra
GroupsSubgroups, cosets and Lagrange's theoremCyclic groups and permutation groupsHomomorphisms, normal subgroups and quotient groupsRings and fieldsGalois theory: why the quintic has no formula