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Multiplicative Group of Complex Numbers

The complex numbers are defined as \[\begin{aligned}\end{aligned}\], where i^2 = -1. If z = a + bi, then a is the real part of z and b is the imaginary part of z. To add two complex numbers z=a+bi and w= c+di,

Multiplicative Group of Complex Numbers

The complex numbers are defined as \[\begin{aligned}\end{aligned}\], where \(i^2 = -1\). If \(z = a + bi\), then \(a\) is the real part of \(z\) and \(b\) is the imaginary part of \(z\).

To add two complex numbers \(z=a+bi\) and \(w= c+di\), we just add the corresponding real and imaginary parts: \[\begin{aligned}\end{aligned}\]. Remembering that \(i^2 = -1\), we multiply complex numbers just like polynomials. The product of \(z\) and \(w\) is \[\begin{aligned}\end{aligned}\].

Every nonzero complex number \(z = a +bi\) has a multiplicative inverse; that is, there exists a \(z^{-1} \in {\mathbb C}^\ast\) such that \(z z^{-1} = z^{-1} z = 1\). If \(z = a + bi\), then \[\begin{aligned}\end{aligned}\]. The complex conjugate of a complex number \(z = a + bi\) is defined to be \(\overline{z} = a- bi\). The absolute value or modulus of \(z = a + bi\) is \(|z| = \sqrt{a^2 + b^2}\).

Example

Let \(z = 2 + 3i\) and \(w = 1-2i\). Then \[\begin{aligned}\end{aligned}\] and \[\begin{aligned}\end{aligned}\]. Also, \[\begin{aligned}z^{-1} & = \frac{2}{13} - \frac{3}{13}i \\ |z| & = \sqrt{13} \\ \overline{z} & = 2-3i\end{aligned}\].

There are several ways of graphically representing complex numbers. We can represent a complex number \(z = a +bi\) as an ordered pair on the \(xy\) plane where \(a\) is the \(x\) (or real) coordinate and \(b\) is the \(y\) (or imaginary) coordinate. This is called the rectangular or Cartesian representation. The rectangular representations of \(z_1 = 2 + 3i\), \(z_2 = 1 - 2i\), and \(z_3 = - 3 + 2i\) are depicted in .

Nonzero complex numbers can also be represented using polar coordinates. To specify any nonzero point on the plane, it suffices to give an angle \(\theta\) from the positive \(x\) axis in the counterclockwise direction and a distance \(r\) from the origin, as in . We can see that \[\begin{aligned}\end{aligned}\]. Hence, \[\begin{aligned}\end{aligned}\] and \[\begin{aligned}a & = r \cos \theta \\ b & = r \sin \theta\end{aligned}\]. We sometimes abbreviate \(r( \cos \theta + i \sin \theta)\) as \(r \cis \theta\). \(\cis \theta\) \(\cos \theta + i \sin \theta\) To assure that the representation of \(z\) is well-defined, we also require that \(0^{\circ} \leq \theta \lt 360^{\circ}\). If the measurement is in radians, then \(0 \leq \theta \lt2 \pi\).

Example

Suppose that \(z = 2 \cis 60^{\circ}\). Then \[\begin{aligned}\end{aligned}\] and \[\begin{aligned}\end{aligned}\]. Hence, the rectangular representation is \(z = 1+\sqrt{3}\, i\).

Conversely, if we are given a rectangular representation of a complex number, it is often useful to know the number's polar representation. If \(z = 3 \sqrt{2} - 3 \sqrt{2}\, i\), then \[\begin{aligned}\end{aligned}\] and \[\begin{aligned}\end{aligned}\], so \(3 \sqrt{2} - 3 \sqrt{2}\, i=6 \cis 315^{\circ}\).

The polar representation of a complex number makes it easy to find products and powers of complex numbers. The proof of the following proposition is straightforward and is left as an exercise.

Example

If \(z = 3 \cis( \pi / 3 )\) and \(w = 2 \cis(\pi / 6 )\), then \(zw = 6 \cis( \pi / 2 ) = 6i\).

Example

Suppose that \(z= 1+i\) and we wish to compute \(z^{10}\). Rather than computing \((1 + i)^{10}\) directly, it is much easier to switch to polar coordinates and calculate \(z^{10}\) using DeMoivre's Theorem: \[\begin{aligned}z^{10} & = (1+i)^{10} \\ & = \left( \sqrt{2} \cis \left( \frac{\pi }{4} \right) \right)^{10} \\ & = ( \sqrt{2}\, )^{10} \cis \left( \frac{5\pi }{2} \right) \\ & = 32 \cis \left( \frac{\pi }{2} \right) \\ & = 32i\end{aligned}\].

The Circle Group and the Roots of Unity

The multiplicative group of the complex numbers, \({\mathbb C}^*\), possesses some interesting subgroups. Whereas \({\mathbb Q}^*\) and \({\mathbb R}^*\) have no interesting subgroups of finite order, \({\mathbb C}^*\) has many. We first consider the circle group, \(\mathbb T\) the circle group \[\begin{aligned}\end{aligned}\]. The following proposition is a direct result of .

Although the circle group has infinite order, it has many interesting finite subgroups. Suppose that \(H = \{ 1, -1, i, -i \}\). Then \(H\) is a subgroup of the circle group. Also, \(1\), \(-1\), \(i\), and \(-i\) are exactly those complex numbers that satisfy the equation \(z^4 = 1\). The complex numbers satisfying the equation \(z^n=1\) are called the \(n\)th roots of unity.

A generator for the group of the \(n\)th roots of unity is called a primitive \(n\)th root of unity.

Example

The 8th roots of unity can be represented as eight equally spaced points on the unit circle (). The primitive 8th roots of unity are \[\begin{aligned}\omega & = \frac{\sqrt{2}}{2} + \frac{\sqrt{2}}{2} i \\ \omega^3 & = -\frac{\sqrt{2}}{2} + \frac{\sqrt{2}}{2} i \\ \omega^5 & = -\frac{\sqrt{2}}{2} - \frac{\sqrt{2}}{2} i \\ \omega^7 & = \frac{\sqrt{2}}{2} - \frac{\sqrt{2}}{2}i\end{aligned}\].

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What is a group, in plain words?

A set with one operation that is associative, has an identity, and lets every element be undone. Symmetries of any object form a group. That is where the idea came from.

What is the difference between a ring and a field?

A ring has addition and multiplication that behave like the integers (you cannot always divide); a field is a ring where every non-zero element has a reciprocal, like the rationals or the reals.

이 페이지의 일부는 다음에서 변경되었습니다. Judson, Abstract Algebra: Theory and Applications (GFDL 1.3). 여기서 압축하고 다시 설명; 오류는 우리의.

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