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Isku-duwaha, derivatives, integrals, matrices, saddex geesoodka, primes, tirakoobka, ama dhibaato eray ah ee tutor qaybaha ka qayb qaadataa.
Y'' + 4y' + 4y = 0
4 y{\left(x \right)} + 4 \frac{d}{d x} y{\left(x \right)} + \frac{d^{2}}{d x^{2}} y{\left(x \right)} = 0
tallaabo tallaabo
- 4 y{\left(x \right)} + 4 \frac{d}{d x} y{\left(x \right)} + \frac{d^{2}}{d x^{2}} y{\left(x \right)} = 0
The differential equation.
- \text{order } 2
Order 2: the highest derivative present.
- \text{Constant coefficients, homogeneous}
Try y = e^{rx}: the characteristic polynomial in r gives the roots, and each root contributes a term to the general solution.
- r^{2} + 4 r + 4 = 0
Characteristic equation of the homogeneous part (substitute y = e^{rx}).
- r = -2\ (\times 2)
Its roots.
- y{\left(x \right)} = \left(C_{1} + C_{2} x\right) e^{- 2 x}
General solution (C₁, C₂ … are arbitrary constants).
- \checkmark
Verified: substituting the solution back into the equation gives 0.
Jawaabta muuji
y{\left(x \right)} = \left(C_{1} + C_{2} x\right) e^{- 2 x}