Реши било који проблем са математиком.

Корак по корак

1. a = 4,\ b = 4,\ c = 4

   Three sides (SSS). Check the triangle inequality: each side is less than the sum of the other two. ✓

2. P = a + b + c = 12

   Perimeter.

3. s = \tfrac{P}{2} = 6,\quad A = \sqrt{s(s-a)(s-b)(s-c)} = 4 \sqrt{3} \approx 6.9282

   Heron's formula for the area.

4. \cos A = \frac{b^2 + c^2 - a^2}{2bc} = \frac{1}{2} \Rightarrow A \approx 60.000^\circ

   Law of cosines for angle A (opposite side a).

5. \cos B = \frac{a^2 + c^2 - b^2}{2ac} = \frac{1}{2} \Rightarrow B \approx 60.000^\circ

   Law of cosines for angle B (opposite side b).

6. \cos C = \frac{a^2 + b^2 - c^2}{2ab} = \frac{1}{2} \Rightarrow C \approx 60.000^\circ

   Law of cosines for angle C (opposite side c).

7. A + B + C = 180.0^\circ

   The angles add to 180° — a acute, equilateral triangle.