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قدم ب قدم
- f(x) = \frac{1}{- x^{2} - x + 1}
Taylor series about x = 0: f(x) = Σ fᵏ(x₀)/k! · (x − x₀)ᵏ.
- f^{(0)}(0) = \frac{1}{- x^{2} - x + 1}\big|_{x=0} = 1
Derivative 0 at the centre.
- f^{(1)}(0) = \frac{2 x + 1}{\left(- x^{2} - x + 1\right)^{2}}\big|_{x=0} = 1
Derivative 1 at the centre.
- f^{(2)}(0) = \frac{2 \left(- \frac{\left(2 x + 1\right)^{2}}{x^{2} + x - 1} + 1\right)}{\left(x^{2} + x - 1\right)^{2}}\big|_{x=0} = 4
Derivative 2 at the centre.
- f^{(3)}(0) = \frac{6 \left(2 x + 1\right) \left(\frac{\left(2 x + 1\right)^{2}}{x^{2} + x - 1} - 2\right)}{\left(x^{2} + x - 1\right)^{3}}\big|_{x=0} = 18
Derivative 3 at the centre.
- f^{(4)}(0) = \frac{24 \left(- \frac{\left(2 x + 1\right)^{4}}{\left(x^{2} + x - 1\right)^{2}} + \frac{3 \left(2 x + 1\right)^{2}}{x^{2} + x - 1} - 1\right)}{\left(x^{2} + x - 1\right)^{3}}\big|_{x=0} = 120
Derivative 4 at the centre.
- f^{(5)}(0) = \frac{120 \left(2 x + 1\right) \left(\frac{\left(2 x + 1\right)^{4}}{\left(x^{2} + x - 1\right)^{2}} - \frac{4 \left(2 x + 1\right)^{2}}{x^{2} + x - 1} + 3\right)}{\left(x^{2} + x - 1\right)^{4}}\big|_{x=0} = 960
Derivative 5 at the centre.
- 8 x^{5} + 5 x^{4} + 3 x^{3} + 2 x^{2} + x + 1
Assemble the terms up to degree 5.
جواب کھوليں
8 x^{5} + 5 x^{4} + 3 x^{3} + 2 x^{2} + x + 1 + O((x-0)^{6})