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ਕਦਮ ਦਰ ਕਦਮ

1. f(x) = x^{2}

   Tangent line at x = 1: y = f(x₀) + f′(x₀)(x − x₀).

2. f(1) = 1

   The point of tangency.

3. f'(x) = 2 x,\quad f'(1) = 2

   The slope is the derivative there.

4. y = 1 + 2(x - 1) = 2 x - 1

   Point-slope form, simplified.

ਜਵਾਬ ਦਿਓ

y = 2 x - 1