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Linear-Algebra · Rank

Rank of [[1,2,3],[4,5,6],[7,8,9]]

\left[\begin{matrix}1 & 2 & 3\\4 & 5 & 6\\7 & 8 & 9\end{matrix}\right]

Step by step

  1. \left[\begin{matrix}1 & 2 & 3\\4 & 5 & 6\\7 & 8 & 9\end{matrix}\right]

    Row-reduce; the rank is the number of non-zero rows (pivots).

  2. \left[\begin{matrix}1 & 2 & 3\\0 & -3 & -6\\7 & 8 & 9\end{matrix}\right]

    R2 ← R2 − (4)·R1 to clear column 1.

  3. \left[\begin{matrix}1 & 2 & 3\\0 & -3 & -6\\0 & -6 & -12\end{matrix}\right]

    R3 ← R3 − (7)·R1 to clear column 1.

  4. \left[\begin{matrix}1 & 2 & 3\\0 & 1 & 2\\0 & -6 & -12\end{matrix}\right]

    R2 ← R2 / -3 to make the pivot 1.

  5. \left[\begin{matrix}1 & 0 & -1\\0 & 1 & 2\\0 & -6 & -12\end{matrix}\right]

    R1 ← R1 − (2)·R2 to clear column 2.

  6. \left[\begin{matrix}1 & 0 & -1\\0 & 1 & 2\\0 & 0 & 0\end{matrix}\right]

    R3 ← R3 − (-6)·R2 to clear column 2.

  7. \operatorname{rank} A = 2

Reveal the answer
\operatorname{rank} A = 2