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Limit of sinh(n)/n^2 as n → oo
\lim_{n \to \infty} \frac{\sinh{\left(n \right)}}{n^{2}}
Step by step
- \lim_{n \to \infty^+-} \frac{\sinh{\left(n \right)}}{n^{2}}
Try direct substitution first.
- \
As x grows without bound, compare the fastest-growing terms (or divide top and bottom by the highest power).
- = \infty
Take the limit.
Reveal the answer
\infty