Solve any maths problem
Equations, derivatives, integrals, matrices, triangles, primes, statistics, or a word problem the tutor breaks into parts.
Integrate y·(1 - y)/2 from 0 to 1
\int_{0}^{1} \frac{y \left(1 - y\right)}{2}\, dy
Step by step
- \int_{0}^{1} \frac{y \left(1 - y\right)}{2}\, dy
First find an antiderivative F, then evaluate F(b) − F(a).
- \int \frac{y \left(1 - y\right)}{2}\, dy = \frac{1}{2} \int y \left(1 - y\right)\, dy
Pull the constant \frac{1}{2} out of the integral.
- u = - y,\quad du = -1\, dy
Substitute u = - y.
- \int y \left(1 - y\right)\, dy = \int u^{2} + u\, d_u
Rewrite the integral in terms of u.
- \int u^{2} + u\, d_u = \int u^{2}\, d_u + \int u\, d_u
The integral of a sum is the sum of the integrals.
- \int u^{2}\, d_u = \frac{u^{3}}{3}
Power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1) (n ≠ −1).
- \int u\, d_u = \frac{u^{2}}{2}
Power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1) (n ≠ −1).
- = - \frac{y^{3}}{3} + \frac{y^{2}}{2}
Substitute back u = - y.
- F(1) - F(0) = \left(\frac{1}{12}\right) - \left(0\right)
Fundamental theorem of calculus: plug in the limits.
- = \frac{1}{12}
Simplify.
Reveal the answer
\frac{1}{12}