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Integrate y·(1 - y)/2 from 0 to 1

\int_{0}^{1} \frac{y \left(1 - y\right)}{2}\, dy

Step by step

  1. \int_{0}^{1} \frac{y \left(1 - y\right)}{2}\, dy

    First find an antiderivative F, then evaluate F(b) − F(a).

  2. \int \frac{y \left(1 - y\right)}{2}\, dy = \frac{1}{2} \int y \left(1 - y\right)\, dy

    Pull the constant \frac{1}{2} out of the integral.

  3. u = - y,\quad du = -1\, dy

    Substitute u = - y.

  4. \int y \left(1 - y\right)\, dy = \int u^{2} + u\, d_u

    Rewrite the integral in terms of u.

  5. \int u^{2} + u\, d_u = \int u^{2}\, d_u + \int u\, d_u

    The integral of a sum is the sum of the integrals.

  6. \int u^{2}\, d_u = \frac{u^{3}}{3}

    Power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1) (n ≠ −1).

  7. \int u\, d_u = \frac{u^{2}}{2}

    Power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1) (n ≠ −1).

  8. = - \frac{y^{3}}{3} + \frac{y^{2}}{2}

    Substitute back u = - y.

  9. F(1) - F(0) = \left(\frac{1}{12}\right) - \left(0\right)

    Fundamental theorem of calculus: plug in the limits.

  10. = \frac{1}{12}

    Simplify.

Reveal the answer
\frac{1}{12}