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Integrate x·e^(-x^2) from 0 to oo
\int_{0}^{\infty} x e^{- x^{2}}\, dx
Step by step
- \int_{0}^{\infty} x e^{- x^{2}}\, dx
First find an antiderivative F, then evaluate F(b) − F(a).
- u = e^{- x^{2}},\quad du = - 2 x e^{- x^{2}}\, dx
Substitute u = e^{- x^{2}}.
- \int x e^{- x^{2}}\, dx = \int - \frac{1}{2}\, d_u
Rewrite the integral in terms of u.
- \int - \frac{1}{2}\, d_u = - \frac{1}{2} \int 1\, d_u
Pull the constant - \frac{1}{2} out of the integral.
- \int 1\, d_u = u
The integral of a constant c is c·x.
- = - \frac{e^{- x^{2}}}{2}
Substitute back u = e^{- x^{2}}.
- F(\infty) - F(0) = \left(0\right) - \left(- \frac{1}{2}\right)
Fundamental theorem of calculus: plug in the limits.
- = \frac{1}{2}
Simplify.
Reveal the answer
\frac{1}{2}