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ਕਦਮ ਦਰ ਕਦਮ

1. \int_{0}^{\infty} e^{- x}\, dx

   First find an antiderivative F, then evaluate F(b) − F(a).

2. u = - x,\quad du = -1\, dx

   Substitute u = - x.

3. \int e^{- x}\, dx = \int - e^{u}\, d_u

   Rewrite the integral in terms of u.

4. \int - e^{u}\, d_u = -1 \int e^{u}\, d_u

   Pull the constant -1 out of the integral.

5. \int e^{u}\, d_u = e^{u}

   ∫ aᵘ du = aᵘ / ln a (for eˣ that is just eˣ).

6. = - e^{- x}

   Substitute back u = - x.

7. F(\infty) - F(0) = \left(0\right) - \left(-1\right)

   Fundamental theorem of calculus: plug in the limits.

8. = 1

   Simplify.

ਜਵਾਬ ਦਿਓ

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