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Integrate (t + 1)^(-2) from 0 to oo
\int_{0}^{\infty} \frac{1}{\left(t + 1\right)^{2}}\, dt
Step by step
- \int_{0}^{\infty} \frac{1}{\left(t + 1\right)^{2}}\, dt
First find an antiderivative F, then evaluate F(b) − F(a).
- u = t + 1,\quad du = 1\, dt
Substitute u = t + 1.
- \int \frac{1}{\left(t + 1\right)^{2}}\, dt = \int \frac{1}{u^{2}}\, d_u
Rewrite the integral in terms of u.
- \int \frac{1}{u^{2}}\, d_u = - \frac{1}{u}
Power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1) (n ≠ −1).
- = - \frac{1}{t + 1}
Substitute back u = t + 1.
- F(\infty) - F(0) = \left(0\right) - \left(-1\right)
Fundamental theorem of calculus: plug in the limits.
- = 1
Simplify.
Reveal the answer
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