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Step by step
- \int \frac{1}{x^{2} - 1}\, dx
Find an antiderivative.
- \frac{1}{x^{2} - 1} = \frac{- \frac{1}{x + 1} + \frac{1}{x - 1}}{2}
Rewrite the integrand into a friendlier form.
- \int \frac{- \frac{1}{x + 1} + \frac{1}{x - 1}}{2}\, dx = \frac{1}{2} \int - \frac{1}{x + 1} + \frac{1}{x - 1}\, dx
Pull the constant \frac{1}{2} out of the integral.
- \int - \frac{1}{x + 1} + \frac{1}{x - 1}\, dx = \int \frac{1}{x - 1}\, dx + \int - \frac{1}{x + 1}\, dx
The integral of a sum is the sum of the integrals.
- \int \frac{1}{x - 1}\, dx = \log{\left(x - 1 \right)}
∫ 1/u du = ln|u|.
- \int - \frac{1}{x + 1}\, dx = -1 \int \frac{1}{x + 1}\, dx
Pull the constant -1 out of the integral.
- \int \frac{1}{x + 1}\, dx = \log{\left(x + 1 \right)}
∫ 1/u du = ln|u|.
- F(x) = \frac{\log{\left(x - 1 \right)}}{2} - \frac{\log{\left(x + 1 \right)}}{2} + C
Add the constant of integration.
Kuratidza mhinduro
\frac{\log{\left(x - 1 \right)}}{2} - \frac{\log{\left(x + 1 \right)}}{2} + C