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Differentiate -sin(3t - x)
\frac{d}{dt}\left[- \sin{\left(3 t - x \right)}\right]
Step by step
- \frac{d}{dt}\left[- \sin{\left(3 t - x \right)}\right]
Start from the derivative to compute.
- - \frac{\partial}{\partial t} \sin{\left(3 t - x \right)}
Constant multiple rule: pull the constant out.
- - \cos{\left(3 t - x \right)} \frac{\partial}{\partial t} \left(3 t - x\right)
Chain rule: (sin u)′ = cos u, times u′ where u = 3 t - x.
- - \left(\frac{d}{d t} 3 t + \frac{d}{d t} \left(- x\right)\right) \cos{\left(3 t - x \right)}
Sum rule: differentiate term by term.
- - \cos{\left(3 t - x \right)} \frac{d}{d t} 3 t
The derivative of a constant is 0.
- - 3 \cos{\left(3 t - x \right)} \frac{d}{d t} t
Constant multiple rule: pull the constant out.
- - 3 \cos{\left(3 t - x \right)}
d/dx of x is 1.
Reveal the answer
f'(t) = - 3 \cos{\left(3 t - x \right)}