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Discrete-Math · Counting

52 choose 5

52,\ 5

Step by step

  1. \binom{52}{5} = \frac{52!}{5!\,(52-5)!}

    Unordered selections: n! / (k! (n−k)!).

  2. = \frac{80658175170943878571660636856403766975289505440883277824000000000000}{120 \times 258623241511168180642964355153611979969197632389120000000000} = 2598960

Reveal the answer
\binom{52}{5} = 2598960