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Algebra · Systems-Of-Equations

Solve the system 2x + 3y = 12

\begin{cases}2 x + 3 y = 12 \\ x - y = 1\end{cases}

Step by step

  1. \begin{cases}2 x + 3 y = 12 \\ x - y = 1\end{cases}

    The system has 2 equations in 2 unknowns (x, y).

  2. x = 6 - \frac{3 y}{2}

    From the first equation, express x in terms of y.

  3. 5 - \frac{5 y}{2} = 0

    Substitute that into the second equation, leaving one equation in y.

  4. y = 2

    Solve for y.

  5. x = 6 - \frac{3 y}{2} = 3

    Back-substitute to get x.

Reveal the answer
x = 3,\; y = 2