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Planes in Space

This section expects students to have familiarity with the notation and operations of vectors from .

Planes in Space

This section expects students to have familiarity with the notation and operations of vectors from . We also would like to point to our earlier description of flat objects in space to motivate the difference between lines and planes as our flat objects. The examples and activities in this section are selected to highlight the broad range of ways that information about a plane can be given, including talking about parallel planes, the interaction between equations of planes and lines, and the angle between planes.

This section can be covered in a longer class period alongside Planes. Many exercises in this section include taking information from planes to get information about a related line and vice versa, so you may want to select work from the sections on lines and planes together.

Introduction

In , we saw how to describe a line in \(\R^n\) by setting an initial point and allowing unrestricted movement in a direction given by a direction vector. In this section's Preview Activity, we will be looking at what happens when we allow only movement that is perpendicular to a given direction. Since we will specify the given direction by a vector, we will find the perpendicular directions using orthogonal vectors.

Exploration

We will consider what happens when we allow movement in \(\R^3\) with the restriction that the movement must be orthogonal to \(\vv=\langle 1,2,3 \rangle\).

Find values for \(a_0\) and \(b_0\) such that \(\langle 0,a_0,b_0 \rangle\) is orthogonal to \(\langle 1,2,3\rangle\).

Find values for \(c_0\) and \(d_0\) such that \(\langle c_0,d_0,0 \rangle\) is orthogonal to \(\langle 1,2,3\rangle\).

Find values for \(c_1\) and \(d_1\) such that \(\langle c_1,d_1,1 \rangle\) is orthogonal to \(\langle 1,2,3\rangle\).

Find two other values for each of \(c\) and \(d\) such that \(\langle c,d,1 \rangle\) is orthogonal to \(\langle 1,2,3\rangle\).

Verify that each of the following vectors is also orthogonal to \(\langle 1,2,3 \rangle\).

  • \(\langle -2,-2,2 \rangle\)
  • \(\langle c_0,a_0+d_0,b_0 \rangle\)
  • \(\langle -2c_1,a_0-2d_1,b_0-2 \rangle\)

Put all of the vectors you have computed into the interactive below to visually verify that each of them is orthogonal to \(\langle 1,2,3 \rangle\). You should put the component values of each vector into this array with each vector corresponding to a row. If you do not have eight distinct vectors from the previous parts, multiply one of your repeated vectors by \(-1\) and enter that instead of entering a vector multiple times.

Describe what you think the plot of the set of vectors that are orthogonal to \(\langle 1,2,3 \rangle\) will look like.

Planes in Space

Now that we have a way of describing lines, we would like to develop a means of describing planes in three dimensions. In Section, we studied the coordinate planes and planes parallel to them. In particular, \(x=1\), \(y=-2\), and \(z=\sqrt{3}\) are examples of fundamental planes. In general, the equations of fundamental planes have the form \(coordinate = constant\).

As shown in , any vector in a plane with \(x= \text{constant}\) will be orthogonal to the vector \(\langle 1,0,0 \rangle\), any vector in a plane with \(y= \text{constant}\) will be orthogonal to the vector \(\langle 0,1,0 \rangle\), and any vector in a plane with \(z= \text{constant}\) will be orthogonal to the vector \(\langle 0,0,1 \rangle\). We will use this idea to define a plane in general.

Like the definition of a line, the definition of a plane given above uses a starting point and a vector as the critical pieces of information. For a line, you begin at the starting point and move as much as you want parallel to the given vector (the direction vector). For a plane, you begin at the starting point and move as much as you want orthogonal to the given vector (the normal vector). For a line, you move only in the direction of the given vector whereas on a plane you cannot move at all in the direction of the given vector.

This description of a plane allows us to find the equation of a plane. Assume that \(\vn=\langle a,b,c\rangle\), \(P_0 = (x_0, y_0, z_0)\), and that \(Q=(x,y,z)\) is an arbitrary point on the plane. Since the vector \(\overrightarrow{P_0 Q}\) lies in the plane, it must be perpendicular to \(\vn\). This means that \[\begin{aligned}0 =\mathstrut \amp \vn\cdot\overrightarrow{P_0 Q} \\ =\mathstrut \amp \vn\cdot \big(\langle x,y,z \rangle - \langle x_0, y_0, z_0\rangle\big) \\ =\mathstrut \amp \vn \cdot \langle x-x_0, y-y_0, z-z_0 \rangle \\ =\mathstrut \amp a(x-x_0) + b(y-y_0) + c(z-z_0).\end{aligned}\]

We may now summarize our new equation for a plane.

  • The scalar equation of the plane with normal vector \(\vn =\langle a,b,c \rangle\) containing the point \(P_0 = (x_0, y_0, z_0)\) is \[\begin{aligned}\end{aligned}\].

  • The vector equation of the plane with normal vector \(\vn =\langle a,b,c \rangle\) containing the points \(P_0 = (x_0, y_0, z_0)\) and \(Q = (x,y,z)\) is \[\begin{aligned}\end{aligned}\].

Condensed — the full section is in Boelkins et al., Active Calculus Multivariable.

Practice (1)

Try each one on paper first. Reveal the answer to check; verified ones can be opened in the solver for every step.

  1. Find an equation for the plane that contains both of the lines described in .

    جواب رو نشون بده

    Find the normal vector to the two direction vectors. \(\vu \times \vv = ((1)(5) - (3)(1))\vi - ((-2)(5) - (3)(-2))\vj + ((-2)(1) - (-2)(1))\vk = \langle 2, 4, 0 \rangle\). Use either \((4, -2, 1)\) or \((-4, 2, 17)\) and \(\langle 2, 4, 0 \rangle\) to write the scalar equation of the plane \(2(x + 4) + 4(y - 2) + 0(z - 17) = 2(x + 4) + 4(y - 2) = 0\) or \(2(x - 4) + 4(y + 2) + 0(z - 1) = 2(x - 4) + 4(y + 2) = 0\)

Symbols used here

\sqrt{x},\ \sqrt[n]{x}
square root, n-th root
The non-negative number whose square (n-th power) is x.
\frac{\partial f}{\partial x}
partial derivative
Derivative with respect to x, holding the other variables fixed.
\nabla f
gradient (nabla, del)
Vector of partial derivatives; points uphill.
\int f(x)\,dx,\ \int_a^b
integral
Antiderivative (indefinite) or signed area from a to b (definite).
\iint,\ \oint
double / contour integral
Integral over a region of the plane; integral around a closed curve.
\mathbf{v},\ \vec{v}
vector
A quantity with magnitude and direction; a column of numbers.
\mathbf{u} \cdot \mathbf{v},\ \|\mathbf{v}\|
dot product, norm
Σ u_i v_i; the length of v, √(v·v).

How to: Planes in Space

  1. How is a plane defined in terms of measurements of points and vectors?
  2. What different ways are there to determine a plane through geometric information?

Questions people ask

What is a partial derivative?

The ordinary derivative with respect to one variable while every other variable is frozen — the slope of the surface in one coordinate direction.

What does the gradient point at?

Uphill: the direction of steepest increase, with length equal to that steepest slope. It is perpendicular to the level curves.

خودت امتحان کن

Parts of this page are adapted from Boelkins et al., Active Calculus Multivariable (CC BY-SA 4.0). Condensed and re-explained here; errors are ours.

بیشتر در Multivariable Calculus