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Double and triple integrals
Volume under a surface by iterated integration; changing the order and the coordinates.
∫∫ f dA sums f over a region by integrating one variable at a time (Fubini). Polar coordinates turn circles into rectangles and give the famous ∫e^{−x²} = √π. Picture it: the volume under the surface z = f(x, y) over the region. Think it: the Jacobian is the local scaling factor — the determinant of the derivative — which is why r appears in polar integrals.
Ýüklenen mysal: integrate x^2 dx from 0 to 1
Adım adım
- \int_{0}^{1} x^{2}\, dx
First find an antiderivative F, then evaluate F(b) − F(a).
- \int x^{2}\, dx = \frac{x^{3}}{3}
Power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1) (n ≠ −1).
- F(1) - F(0) = \left(\frac{1}{3}\right) - \left(0\right)
Fundamental theorem of calculus: plug in the limits.
- = \frac{1}{3}
Simplify.
Jawaby görkez
Symbols used here
Antiderivative (indefinite) or signed area from a to b (definite).
2.71828…, the base whose exponential is its own derivative.
Inequalities that allow equality; < and > exclude it.
Derivative with respect to x, holding the other variables fixed.
Vector of partial derivatives; points uphill.
Integral over a region of the plane; integral around a closed curve.
A quantity with magnitude and direction; a column of numbers.
Σ u_i v_i; the length of v, √(v·v).
How to: Double and triple integrals
- First find an antiderivative F, then evaluate F(b) − F(a).
- Power rule: ∫xⁿ dx = xⁿ⁺¹/(n+1) (n ≠ −1).
- Fundamental theorem of calculus: plug in the limits.
- Simplify.
Questions people ask
What is a partial derivative?
The ordinary derivative with respect to one variable while every other variable is frozen — the slope of the surface in one coordinate direction.
What does the gradient point at?
Uphill: the direction of steepest increase, with length equal to that steepest slope. It is perpendicular to the level curves.
Özüňi synla
_Ýaşa Multivariable Calculus
Functions of several variablesPartial derivatives and the gradientOptimisation in several variablesVector fields, line integrals and the big theorems