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Diagonalisation and matrix powers

A = PDP⁻¹, computing Aⁿ, and the matrices that cannot be diagonalised.

With a full set of eigenvectors, A = PDP⁻¹ where D is diagonal, so Aⁿ = PDⁿP⁻¹: Fibonacci in closed form, Markov chains at equilibrium. Picture it: the transformation stretching along eigenvector directions and nothing else. Think it: symmetric matrices always diagonalise with orthogonal eigenvectors (the spectral theorem); defective ones need Jordan form.

କାର୍ଯ୍ୟକାରୀ ଉଦାହରଣ · eigenvalues of [[4,1],[2,3]]

Eigenvalues of [[4,1],[2,3]]

\left[\begin{matrix}4 & 1\\2 & 3\end{matrix}\right]

ପଦକ୍ଷେପ କ୍ରମେ

  1. \det(A - \lambda I) = 0

    Eigenvalues are the roots of the characteristic polynomial.

  2. \det\left[\begin{matrix}4 - \lambda & 1\\2 & 3 - \lambda\end{matrix}\right] = 0

    Subtract λ from the diagonal.

  3. \lambda^{2} - 7 \lambda + 10 = 0

    Expand the determinant.

  4. \left(\lambda - 5\right) \left(\lambda - 2\right) = 0

    Factor.

  5. \lambda = 5, \lambda = 2

    Eigenvalues (with multiplicity).

  6. \lambda = 2:\ (A - \lambda I)\mathbf{v} = 0 \Rightarrow \mathbf{v} = \left[\begin{matrix}- \frac{1}{2}\\1\end{matrix}\right]

    Solve (A − 2I)v = 0 for a basis eigenvector.

  7. \lambda = 5:\ (A - \lambda I)\mathbf{v} = 0 \Rightarrow \mathbf{v} = \left[\begin{matrix}1\\1\end{matrix}\right]

    Solve (A − 5I)v = 0 for a basis eigenvector.

ଉତ୍ତରକୁ ଖୋଲନ୍ତୁ
\lambda = 5,\; \lambda = 2

ଏବେ ଆପଣ ଗୋଟିଏ ସମସ୍ୟା ବାଛନ୍ତୁ, କିମ୍ବା ଆପଣଙ୍କର ନିଜ ସମସ୍ୟାକୁ ଟାଇପ କରନ୍ତୁ କିମ୍ବା ଆଙ୍କନ୍ତୁ। ପ୍ରତ୍ୟେକ ପର୍ଯ୍ୟାୟରେ, ଗୋଟିଏ ଚିତ୍ର, ଉତ୍ତର ଲୁକ୍କାୟିତ ହୋଇଥାଏ ଯେ ପର୍ଯ୍ୟନ୍ତ ଆପଣ ପଚାରନ୍ତି ନାହିଁ।

ଆପଣଙ୍କର ନିଜ କାର୍ଯ୍ୟକୁ ବଜାୟ ରଖନ୍ତୁ

ଗୋଟିଏ ମୁକ୍ତ ଖାତା ପ୍ରତ୍ୟେକ ପାଠରେ ଟିପ୍ପଣୀ ଯୋଗ କରିଥାଏ, ଆପଣ ଯାହା ସମାପ୍ତ କରିଛନ୍ତି ତାହାର ଗୋଟିଏ ରେକର୍ଡ, ଆପଣଙ୍କର ସମାଧାନ ହୋଇଥିବା ସମସ୍ୟାଗୁଡ଼ିକ ଗୋଟିଏ ସ୍ଥାନରେ, ଏବଂ ଜଣେ ଶିକ୍ଷକ ଆପଣ ଏହି ପୃଷ୍ଠା ବିଷୟରେ ପଚାରିପାରିବେ। ଗଣିତ ନିଜେ ସମସ୍ତଙ୍କୁ ଖୋଲା ଅଛି, ଲଗଇନ ହୋଇଥିବା କିମ୍ବା ନଥିବା।

ସଦସ୍ୟତା ନିଅନ୍ତୁ ଲଗଇନ

ଏଠାରେ ବ୍ୟବହୃତ ପ୍ରତୀକଗୁଡିକ

ସମ୍ପୂର୍ଣ୍ଣ ବର୍ଣ୍ଣନା ପାଇଁ ଯେକୌଣସି ପ୍ରତୀକକୁ ଟ୍ୟାପ କରନ୍ତୁ, ଗୋଟିଏ ଚିତ୍ର, ଏବଂ ଏଥିରେ ଥିବା ପ୍ରତ୍ୟେକ ଅକ୍ଷରର ଅର୍ଥ କଣ।

କିପରି: Diagonalisation and matrix powers

  1. Eigenvalues are the roots of the characteristic polynomial.
  2. Subtract λ from the diagonal.
  3. Expand the determinant.
  4. Factor.
  5. Eigenvalues (with multiplicity).
  6. Solve (A − 2I)v = 0 for a basis eigenvector.
  7. Solve (A − 5I)v = 0 for a basis eigenvector.

ଲୋକମାନେ ପଚାରୁଥିବା ପ୍ରଶ୍ନ

What does a determinant mean geometrically?

It is the factor by which the matrix scales area (2×2) or volume (3×3), with a negative sign if orientation flips. Zero means the matrix flattens space and cannot be undone.

What is an eigenvector?

A direction the matrix does not turn: it only stretches it by the eigenvalue. Along eigenvectors a complicated matrix acts like multiplication by a number.

Why is matrix multiplication not commutative?

Because a matrix is a transformation and AB means "do B, then A". Rotating then reflecting is not the same as reflecting then rotating.

ଅଧିକ Linear Algebra