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Use the Rectangular Coordinate System
Plot points on a rectangular coordinate system
Plot Points on a Rectangular Coordinate System
Many maps, such as the Campus Map shown in , use a grid system to identify locations. Do you see the numbers \(1,2,3,\) and \(4\) across the top and bottom of the map and the letters A, B, C, and D along the sides? Every location on the map can be identified by a number and a letter.
For example, the Student Center is in section 2B. It is located in the grid section above the number \(2\) and next to the letter B. In which grid section is the Stadium? The Stadium is in section 4D.
Example
Try it.
Use the map in .
- ⓐ Find the grid section of the Residence Halls.
- ⓑ What is located in grid section 4C?
Solution
- ⓐ Read the number below the Residence Halls, \(4,\) and the letter to the side, A. So the Residence Halls are in grid section 4A.
- ⓑ Find \(4\) across the bottom of the map and C along the side. Look below the \(4\) and next to the C. Tiger Field is in grid section 4C.
Just as maps use a grid system to identify locations, a grid system is used in algebra to show a relationship between two variables in a rectangular coordinate system. To create a rectangular coordinate system, start with a horizontal number line. Show both positive and negative numbers as you did before, using a convenient scale unit. This horizontal number line is called the x-axis.
Now, make a vertical number line passing through the \(x\text{-axis}\) at \(0.\) Put the positive numbers above \(0\) and the negative numbers below \(0.\) See . This vertical line is called the y-axis.
Vertical grid lines pass through the integers marked on the \(x\text{-axis}.\) Horizontal grid lines pass through the integers marked on the \(y\text{-axis}.\) The resulting grid is the rectangular coordinate system.
The rectangular coordinate system is also called the \(x\text{-}y\) plane, the coordinate plane, or the Cartesian coordinate system (since it was developed by a mathematician named René Descartes.)
The \(x\text{-axis}\) and the \(y\text{-axis}\) form the rectangular coordinate system. These axes divide a plane into four areas, called quadrants. The quadrants are identified by Roman numerals, beginning on the upper right and proceeding counterclockwise. See .
Condensed — the full section is in OpenStax Prealgebra 2e.
Identify Points on a Graph
In algebra, being able to identify the coordinates of a point shown on a graph is just as important as being able to plot points. To identify the x-coordinate of a point on a graph, read the number on the x-axis directly above or below the point. To identify the y-coordinate of a point, read the number on the y-axis directly to the left or right of the point. Remember, to write the ordered pair using the correct order \((x,y).\)
Example
Try it.
Name the ordered pair of each point shown:
Solution
Point A is above \(-3\) on the \(x\text{-axis},\) so the \(x\text{-coordinate}\) of the point is \(-3.\) The point is to the left of \(3\) on the \(y\text{-axis},\) so the \(y\text{-coordinate}\) of the point is \(3.\) The coordinates of the point are \((-3,3).\)
Point B is below \(-1\) on the \(x\text{-axis},\) so the \(x\text{-coordinate}\) of the point is \(-1.\) The point is to the left of \(-3\) on the \(y\text{-axis},\) so the \(y\text{-coordinate}\) of the point is \(-3.\) The coordinates of the point are \((-1,-3).\)
Point C is above \(2\) on the \(x\text{-axis},\) so the \(x\text{-coordinate}\) of the point is \(2.\) The point is to the right of \(4\) on the \(y\text{-axis},\) so the \(y\text{-coordinate}\) of the point is \(4.\) The coordinates of the point are \((2,4).\)
Point D is below \(4\) on the \(x-\text{axis},\) so the \(x\text{-coordinate}\) of the point is \(4.\) The point is to the right of \(-4\) on the \(y\text{-axis},\) so the \(y\text{-coordinate}\) of the point is \(-4.\) The coordinates of the point are \((4,-4).\)
Example
Try it.
Name the ordered pair of each point shown:
Solution
| Point A is on the x-axis at \(x=-4\). | The coordinates of point A are \((-4,0)\). |
| Point B is on the y-axis at \(y=-2\) | The coordinates of point B are \((0,-2)\). |
| Point C is on the x-axis at \(x=3\). | The coordinates of point C are \((3,0)\). |
| Point D is on the y-axis at \(y=1\). | The coordinates of point D are \((0,1)\). |
Verify Solutions to an Equation in Two Variables
All the equations we solved so far have been equations with one variable. In almost every case, when we solved the equation we got exactly one solution. The process of solving an equation ended with a statement such as \(x=4.\) Then we checked the solution by substituting back into the equation.
Here’s an example of a linear equation in one variable, and its one solution.
\[\begin{array}{l}3x+5=17 \\ \\ 3x=12 \\ x=4\end{array}\]But equations can have more than one variable. Equations with two variables can be written in the general form \(Ax+By=C.\) An equation of this form is called a linear equation in two variables.
Notice that the word “line” is in linear.
Here is an example of a linear equation in two variables, \(x\) and \(y\text{:}\)
Is \(y=-5x+1\) a linear equation? It does not appear to be in the form \(Ax+By=C.\) But we could rewrite it in this form.
| Add \(5x\) to both sides. | |
| Simplify. | |
| Use the Commutative Property to put it in \(Ax+By=C.\) |
By rewriting \(y=-5x+1\) as \(5x+y=1,\) we can see that it is a linear equation in two variables because it can be written in the form \(Ax+By=C.\)
Example
Try it.
Determine which ordered pairs are solutions of the equation \(x+4y=8\text{:}\)
- ⓐ \(\ (0,2)\)
- ⓑ \(\ (2,-4)\)
- ⓒ \(\ (-4,3)\)
Solution
Substitute the \(x\text{- and}\ y\text{-values}\) from each ordered pair into the equation and determine if the result is a true statement.
| ⓐ \(\ (0,2)\) | ⓑ \(\ (2,-4)\) | ⓒ \(\ (-4,3)\) |
| \((0,2)\) is a solution. | \((2,-4)\) is not a solution. | \((-4,3)\) is a solution. |
Example
Try it.
Determine which ordered pairs are solutions of the equation. \(y=5x-1\text{:}\)
- ⓐ \(\ (0,-1)\)
- ⓑ \(\ (1,4)\)
- ⓒ \(\ (-2,-7)\)
Solution
Substitute the \(x\text{-}\) and \(y\text{-values}\) from each ordered pair into the equation and determine if it results in a true statement.
| ⓐ \(\ (0,-1)\) | ⓑ \(\ (1,4)\) | ⓒ \(\ (-2,-7)\) |
| \((0,-1)\) is a solution. | \((1,4)\) is a solution. | \((-2,-7)\) is not a solution. |
Condensed — the full section is in OpenStax Prealgebra 2e.
Complete a Table of Solutions to a Linear Equation
In the previous examples, we substituted the \(x\text{- and}\ y\text{-values}\) of a given ordered pair to determine whether or not it was a solution to a linear equation. But how do we find the ordered pairs if they are not given? One way is to choose a value for \(x\) and then solve the equation for \(y.\) Or, choose a value for \(y\) and then solve for \(x.\)
We’ll start by looking at the solutions to the equation \(y=5x-1\) we found in . We can summarize this information in a table of solutions.
| \(y=5x-1\) | ||
| \(x\) | \(y\) | \((x,y)\) |
| \(0\) | \(-1\) | \((0,-1)\) |
| \(1\) | \(4\) | \((1,4)\) |
To find a third solution, we’ll let \(x=2\) and solve for \(y.\)
| \(y=5x-1\) | |
| Multiply. | \(y=10-1\) |
| Simplify. | \(y=9\) |
The ordered pair is a solution to \(y=5x-1\). We will add it to the table.
| \(y=5x-1\) | ||
| \(x\) | \(y\) | \((x,y)\) |
| \(0\) | \(-1\) | \((0,-1)\) |
| \(1\) | \(4\) | \((1,4)\) |
| \(2\) | \(9\) | \((2,9)\) |
We can find more solutions to the equation by substituting any value of \(x\) or any value of \(y\) and solving the resulting equation to get another ordered pair that is a solution. There are an infinite number of solutions for this equation.
Example
Try it.
Complete the table to find three solutions to the equation \(y=4x-2\text{:}\)
| \(y=4x-2\) | ||
| \(x\) | \(y\) | \((x,y)\) |
| \(0\) | ||
| \(-1\) | ||
| \(2\) |
Solution
Substitute \(x=0,x=-1,\) and \(x=2\) into \(y=4x-2.\)
| \(y=4x-2\) | \(y=4x-2\) | \(y=4x-2\) |
| \(y=0-2\) | \(y=-4-2\) | \(y=8-2\) |
| \(y=-2\) | \(y=-6\) | \(y=6\) |
| \((0,-2)\) | \((-1,-6)\) | \((2,6)\) |
The results are summarized in the table.
| \(y=4x-2\) | ||
| \(x\) | \(y\) | \((x,y)\) |
| \(0\) | \(-2\) | \((0,-2)\) |
| \(-1\) | \(-6\) | \((-1,-6)\) |
| \(2\) | \(6\) | \((2,6)\) |
Example
Try it.
Complete the table to find three solutions to the equation \(5x-4y=20\text{:}\)
| \(5x-4y=20\) | ||
| \(x\) | \(y\) | \((x,y)\) |
| \(0\) | ||
| \(0\) | ||
| \(5\) |
Solution
The results are summarized in the table.
| \(5x-4y=20\) | ||
| \(x\) | \(y\) | \((x,y)\) |
| \(0\) | \(-5\) | \((0,-5)\) |
| \(4\) | \(0\) | \((4,0)\) |
| \(8\) | \(5\) | \((8,5)\) |
Find Solutions to Linear Equations in Two Variables
To find a solution to a linear equation, we can choose any number we want to substitute into the equation for either \(x\) or \(y.\) We could choose \(1,100,1,000,\) or any other value we want. But it’s a good idea to choose a number that’s easy to work with. We’ll usually choose \(0\) as one of our values.
Example
Try it.
Find a solution to the equation \(3x+2y=6.\)
Solution
| Step 1: Choose any value for one of the variables in the equation. | We can substitute any value we want for \(\ x\\) or any value for \(\ y.\) Let's pick \(x=0.\) What is the value of \(\ y\\) if \(\ x=0\)? | |
| Step 2: Substitute that value into the equation. Solve for the other variable. | Substitute \(0\) for \(\ x.\) Simplify. Divide both sides by 2. | |
| Step 3: Write the solution as an ordered pair. | So, when \(x=0,y=3.\) | This solution is represented by the ordered pair \((0,3).\) |
| Step 4: Check. |
Is the result a true equation? Yes! |
We said that linear equations in two variables have infinitely many solutions, and we’ve just found one of them. Let’s find some other solutions to the equation \(3x+2y=6.\)
Example
Try it.
Find three more solutions to the equation \(3x+2y=6.\)
Solution
To find solutions to \(3x+2y=6,\) choose a value for \(x\) or \(y.\) Remember, we can choose any value we want for \(x\) or \(y.\) Here we chose \(1\) for \(x,\) and \(0\) and \(-3\) for \(y.\)
| Substitute it into the equation. | |||
| Simplify.
Solve. | |||
| Write the ordered pair. | \((2,0)\) | \((1,\frac{3}{2})\) | \((4,-3)\) |
Check your answers.
| \((2,0)\) | \((1,\frac{3}{2})\) | \((4,-3)\) |
So \((2,0),(1,\frac{3}{2})\) and \((4,-3)\) are all solutions to the equation \(3x+2y=6.\) In the previous example, we found that \((0,3)\) is a solution, too. We can list these solutions in a table.
| \(3x+2y=6\) | ||
| \(x\) | \(y\) | \((x,y)\) |
| \(0\) | \(3\) | \((0,3)\) |
| \(2\) | \(0\) | \((2,0)\) |
| \(1\) | \(\frac{3}{2}\) | \((1,\frac{3}{2})\) |
| \(4\) | \(-3\) | \((4,-3)\) |
Let’s find some solutions to another equation now.
Example
Try it.
Find three solutions to the equation \(x-4y=8.\)
Solution
| Choose a value for \(x\) or \(y.\) | |||
| Substitute it into the equation. | |||
| Solve. | |||
| Write the ordered pair. | \((0,-2)\) | \((8,0)\) | \((20,3)\) |
So \((0,-2),(8,0),\) and \((20,3)\) are three solutions to the equation \(x-4y=8.\)
| \(x-4y=8\) | ||
| \(x\) | \(y\) | \((x,y)\) |
| \(0\) | \(-2\) | \((0,-2)\) |
| \(8\) | \(0\) | \((8,0)\) |
| \(20\) | \(3\) | \((20,3)\) |
Remember, there are an infinite number of solutions to each linear equation. Any point you find is a solution if it makes the equation true.
Condensed — the full section is in OpenStax Prealgebra 2e.
Key Concepts
- Sign Patterns of the Quadrants
Quadrant I Quadrant II Quadrant III Quadrant IV (x,y) (x,y) (x,y) (x,y) (+,+) (−,+) (−,−) (+,−) - Coordinates of Zero
- Points with a y-coordinate equal to 0 are on the x-axis, and have coordinates ( a, 0).
- Points with a x-coordinate equal to 0 are on the y-axis, and have coordinates ( 0, b).
- The point (0, 0) is called the origin. It is the point where the x-axis and y-axis intersect.
Use the Rectangular Coordinate System
Plot Points on a Rectangular Coordinate System
In the following exercises, plot each point on a coordinate grid.
Try it.
\((3,2)\)
Solution
Try it.
\((4,1)\)
Try it.
\((1,5)\)
Solution
Try it.
\((3,4)\)
Try it.
\((4,1),(1,4)\)
Solution
Try it.
\((3,2),(2,3)\)
Try it.
\((3,4),(4,3)\)
Solution
In the following exercises, plot each point on a coordinate grid and identify the quadrant in which the point is located.
Try it.
- ⓐ \(\ (-4,2)\)
- ⓑ \(\ (-1,-2)\)
- ⓒ \(\ (3,-5)\)
- ⓓ \(\ (2,\frac{5}{2})\)
Try it.
- ⓐ \(\ (-2,-3)\)
- ⓑ \(\ (3,-3)\)
- ⓒ \(\ (-4,1)\)
- ⓓ \(\ (1,\frac{3}{2})\)
Solution
Try it.
- ⓐ \(\ (-1,1)\)
- ⓑ \(\ (-2,-1)\)
- ⓒ \(\ (1,-4)\)
- ⓓ \(\ (3,\frac{7}{2})\)
In the following exercises, plot each point on a coordinate grid.
Try it.
- ⓐ \(\ (3,-2)\)
- ⓑ \(\ (-3,2)\)
- ⓒ \(\ (-3,-2)\)
- ⓓ \(\ (3,2)\)
Solution
Try it.
- ⓐ \(\ (4,-1)\)
- ⓑ \(\ (-4,1)\)
- ⓒ \(\ (-4,-1)\)
- ⓓ \(\ (4,1)\)
Try it.
- ⓐ \(\ (-2,0)\)
- ⓑ \(\ (-3,0)\)
- ⓒ \(\ (0,4)\)
- ⓓ \(\ (0,2)\)
Solution
Identify Points on a Graph
In the following exercises, name the ordered pair of each point shown.
Try it.
Try it.
Solution
C(1, -3) D(4, 3)
Try it.
Try it.
Solution
S(-2, 4) T(-4, -2)
Try it.
Try it.
Solution
C(0, -1) D(-1, 0)
Try it.
Verify Solutions to an Equation in Two Variables
In the following exercises, determine which ordered pairs are solutions to the given equation.
Try it.
\(2x+y=6\)
- ⓐ \(\ (1,4)\)
- ⓑ \(\ (3,0)\)
- ⓒ \(\ (2,3)\)
Solution
ⓐ , ⓑ
Try it.
\(x+3y=9\)
- ⓐ \(\ (0,3)\)
- ⓑ \(\ (6,1)\)
- ⓒ \(\ (-3,-3)\)
Try it.
\(4x-2y=8\)
- ⓐ \(\ (3,2)\)
- ⓑ \(\ (1,4)\)
- ⓒ \(\ (0,-4)\)
Solution
ⓐ , ⓒ
Try it.
\(3x-2y=12\)
- ⓐ \(\ (4,0)\)
- ⓑ \(\ (2,-3)\)
- ⓒ \(\ (1,6)\)
Try it.
\(y=4x+3\)
- ⓐ \(\ (4,3)\)
- ⓑ \(\ (-1,-1)\)
- ⓒ \(\ (\frac{1}{2},5)\)
Solution
ⓑ , ⓒ
Try it.
\(y=2x-5\)
- ⓐ \(\ (0,-5)\)
- ⓑ \(\ (2,1)\)
- ⓒ \(\ (\frac{1}{2},-4)\)
Try it.
\(y=\frac{1}{2}x-1\)
- ⓐ \(\ (2,0)\)
- ⓑ \(\ (-6,-4)\)
- ⓒ \(\ (-4,-1)\)
Solution
ⓐ , ⓑ
Try it.
\(y=\frac{1}{3}x+1\)
- ⓐ \(\ (-3,0)\)
- ⓑ \(\ (9,4)\)
- ⓒ \(\ (-6,-1)\)
Find Solutions to Linear Equations in Two Variables
In the following exercises, complete the table to find solutions to each linear equation.
Try it.
\(y=2x-4\)
| \(x\) | \(y\) | \((x,y)\) |
| \(-1\) | ||
| \(0\) | ||
| \(2\) |
Solution
| \(x\) | \(y\) | \((x,y)\) |
| \(-1\) | \(-6\) | \((-1,-6)\) |
| \(0\) | \(-4\) | \((0,-4)\) |
| \(2\) | \(0\) | \((2,0)\) |
Try it.
\(y=3x-1\)
| \(x\) | \(y\) | \((x,y)\) |
| \(-1\) | ||
| \(0\) | ||
| \(2\) |
Try it.
\(y=-x+5\)
| \(x\) | \(y\) | \((x,y)\) |
| \(-2\) | ||
| \(0\) | ||
| \(3\) |
Solution
| \(x\) | \(y\) | \((x,y)\) |
| \(-2\) | \(7\) | \((-2,7)\) |
| \(0\) | \(5\) | \((0,5)\) |
| \(3\) | \(2\) | \((3,2)\) |
Try it.
\(y=\frac{1}{3}x+1\)
| \(x\) | \(y\) | \((x,y)\) |
| \(0\) | ||
| \(3\) | ||
| \(6\) |
Try it.
\(y=-\frac{3}{2}x-2\)
| \(x\) | \(y\) | \((x,y)\) |
| \(-2\) | ||
| \(0\) | ||
| \(2\) |
Solution
| \(x\) | \(y\) | \((x,y)\) |
| \(-2\) | \(1\) | \((-2,1)\) |
| \(0\) | \(-2\) | \((0,-2)\) |
| \(2\) | \(-5\) | \((2,-5)\) |
Try it.
\(x+2y=8\)
| \(x\) | \(y\) | \((x,y)\) |
| \(0\) | ||
| \(4\) | ||
| \(0\) |
Try it.
Have you ever used a map with a rectangular coordinate system? Describe the map and how you used it.
Solution
Answers may vary.
Try it.
How do you determine if an ordered pair is a solution to a given equation?
Condensed — the full section is in OpenStax Prealgebra 2e.
Practice (40)
Try each one on paper first. Reveal the answer to check; verified ones can be opened in the solver for every step.
-
Evaluate: \(x+3\) when \(x=-1.\)
If you missed this problem, review .Ipahayag ang sagot
\(2\)
-
Evaluate: \(2x-5y\) when \(x=3,y=-2.\)
If you missed this problem, review .Ipahayag ang sagot
\(16\)
-
Solve for \(y\text{:}\ 40-4y=20.\)
If you missed this problem, review .Ipahayag ang sagot
\(5\)
-
Use the map in .
- ⓐ Find the grid section of the Residence Halls.
- ⓑ What is located in grid section 4C?
Ipahayag ang sagot
- ⓐ Read the number below the Residence Halls, \(4,\) and the letter to the side, A. So the Residence Halls are in grid section 4A.
- ⓑ Find \(4\) across the bottom of the map and C along the side. Look below the \(4\) and next to the C. Tiger Field is in grid section 4C.
-
Use the map in .
- ⓐ Find the grid section of Taylor Hall.
- ⓑ What is located in section 3B?
Ipahayag ang sagot
- ⓐ 1C
- ⓑ Engineering Building
-
Use the map in .
- ⓐ Find the grid section of the Parking Garage.
- ⓑ What is located in section 2C?
Ipahayag ang sagot
- ⓐ 1A
- ⓑ Library
-
Plot \((1,3)\) and \((3,1)\) in the same rectangular coordinate system.
Ipahayag ang sagot
The coordinate values are the same for both points, but the \(x\) and \(y\) values are reversed. Let’s begin with point \((1,3).\) The \(x\text{-coordinate}\) is \(1\) so find \(1\) on the \(x\text{-axis}\) and sketch a vertical line through \(x=1.\) The \(y\text{-coordinate}\) is \(3\) so we find \(3\) on the \(y\text{-axis}\) and sketch a horizontal line through \(y=3.\) Where the two lines meet, we plot the point \((1,3).\)
To plot the point \((3,1),\) we start by locating \(3\) on the \(x\text{-axis}\) and sketch a vertical line through \(x=3.\) Then we find \(1\) on the \(y\text{-axis}\) and sketch a horizontal line through \(y=1.\) Where the two lines meet, we plot the point \((3,1).\)
Notice that the order of the coordinates does matter, so, \((1,3)\) is not the same point as \((3,1).\)
-
Plot each point on the same rectangular coordinate system: \((5,2),(2,5).\)
Ipahayag ang sagot
-
Plot each point on the same rectangular coordinate system: \((4,2),(2,4).\)
Ipahayag ang sagot
-
Plot each point in the rectangular coordinate system and identify the quadrant in which the point is located:
- ⓐ \(\ (-1,3)\)
- ⓑ \(\ (-3,-4)\)
- ⓒ \(\ (2,-3)\)
- ⓓ \((3,\frac{5}{2})\)
Ipahayag ang sagot
The first number of the coordinate pair is the \(x\text{-coordinate},\) and the second number is the \(y\text{-coordinate}.\)
ⓐ Since \(x=-1,y=3,\) the point \((-1,3)\) is in Quadrant II.
ⓑ Since \(x=-3,y=-4,\) the point \((-3,-4)\) is in Quadrant III.
ⓒ Since \(x=2,y=-1,\) the point \((2,-1)\) is in Quadrant lV.
ⓓ Since \(x=3,y=\frac{5}{2},\) the point \((3,\frac{5}{2})\) is in Quadrant I. It may be helpful to write \(\frac{5}{2}\) as the mixed number, \(2\frac{1}{2},\) or decimal, \(2.5.\) Then we know that the point is halfway between \(2\) and \(3\) on the \(y\text{-axis}.\)
-
Plot each point on a rectangular coordinate system and identify the quadrant in which the point is located.
- ⓐ \(\ (-2,1)\\)
- ⓑ \(\ (-3,-1)\)
- ⓒ \(\ (4,-4)\)
- ⓓ \(\ (-4,\frac{3}{2})\)
Ipahayag ang sagot
(a) Quadrant II, (b) Quadrant III, (c) Quadrant IV, (d) Quadrant II
-
Plot each point on a rectangular coordinate system and identify the quadrant in which the point is located.
- ⓐ \(\ (-4,1)\)
- ⓑ \(\ (-2,3)\)
- ⓒ \(\ (2,-5)\)
- ⓓ \(\ (-3,\frac{5}{2})\)
Ipahayag ang sagot
(a) Quadrant II, (b) Quadrant II, (c) Quadrant IV, (d) Quadrant II
-
Plot each point:
- ⓐ \(\ (-5,2)\)
- ⓑ \(\ (-5,-2)\)
- ⓒ \(\ (5,2)\)
- ⓓ \(\ (5,-2)\)
Ipahayag ang sagot
As we locate the \(x\text{-coordinate}\) and the \(y\text{-coordinate},\) we must be careful with the signs.
-
Plot each point:
- ⓐ \(\ (4,-3)\)
- ⓑ \(\ (4,3)\)
- ⓒ \(\ (-4,-3)\)
- ⓓ \(\ (-4,3)\)
Ipahayag ang sagot
-
Plot each point:
- ⓐ \(\ (-1,4)\)
- ⓑ \(\ (1,4)\)
- ⓒ \(\ (1,-4)\)
- ⓓ \(\ (-1,-4)\)
Ipahayag ang sagot
-
Plot each point on a coordinate grid:
- ⓐ \(\ (0,5)\)
- ⓑ \(\ (4,0)\)
- ⓒ \(\ (-3,0)\)
- ⓓ \(\ (0,0)\)
- ⓔ \(\ (0,-1)\)
Ipahayag ang sagot
- ⓐ Since \(x=0,\) the point whose coordinates are \((0,5)\) is on the \(y\text{-axis}.\)
- ⓑ Since \(y=0,\) the point whose coordinates are \((4,0)\) is on the \(x\text{-axis}.\)
- ⓒ Since \(y=0,\) the point whose coordinates are \((-3,0)\) is on the \(x\text{-axis}.\)
- ⓓ Since \(x=0\) and \(y=0,\) the point whose coordinates are \((0,0)\) is the origin.
- ⓔ Since \(x=0,\) the point whose coordinates are \((0,-1)\) is on the \(y\text{-axis}.\)
-
Plot each point on a coordinate grid:
- ⓐ \(\ (4,0)\)
- ⓑ \(\ (-2,0)\)
- ⓒ \(\ (0,0)\)
- ⓓ \(\ (0,2)\)
- ⓔ \(\ (0,-3)\)
Ipahayag ang sagot
-
Plot each point on a coordinate grid:
- ⓐ \(\ (-5,0)\)
- ⓑ \(\ (3,0)\)
- ⓒ \(\ (0,0)\)
- ⓓ \(\ (0,-1)\)
- ⓔ \(\ (0,4)\)
Ipahayag ang sagot
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Name the ordered pair of each point shown:
Ipahayag ang sagot
Point A is above \(-3\) on the \(x\text{-axis},\) so the \(x\text{-coordinate}\) of the point is \(-3.\) The point is to the left of \(3\) on the \(y\text{-axis},\) so the \(y\text{-coordinate}\) of the point is \(3.\) The coordinates of the point are \((-3,3).\)
Point B is below \(-1\) on the \(x\text{-axis},\) so the \(x\text{-coordinate}\) of the point is \(-1.\) The point is to the left of \(-3\) on the \(y\text{-axis},\) so the \(y\text{-coordinate}\) of the point is \(-3.\) The coordinates of the point are \((-1,-3).\)
Point C is above \(2\) on the \(x\text{-axis},\) so the \(x\text{-coordinate}\) of the point is \(2.\) The point is to the right of \(4\) on the \(y\text{-axis},\) so the \(y\text{-coordinate}\) of the point is \(4.\) The coordinates of the point are \((2,4).\)
Point D is below \(4\) on the \(x-\text{axis},\) so the \(x\text{-coordinate}\) of the point is \(4.\) The point is to the right of \(-4\) on the \(y\text{-axis},\) so the \(y\text{-coordinate}\) of the point is \(-4.\) The coordinates of the point are \((4,-4).\)
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Name the ordered pair of each point shown:
Ipahayag ang sagot
- A: (5,1)
- B: (−2,4)
- C: (−5,−1)
- D: (3,−2)
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Name the ordered pair of each point shown:
Ipahayag ang sagot
- A: (4,2)
- B: (−2,3)
- C: (−4,−4)
- D: (3,−5)
-
Name the ordered pair of each point shown:
Ipahayag ang sagot
Point A is on the x-axis at \(x=-4\). The coordinates of point A are \((-4,0)\). Point B is on the y-axis at \(y=-2\) The coordinates of point B are \((0,-2)\). Point C is on the x-axis at \(x=3\). The coordinates of point C are \((3,0)\). Point D is on the y-axis at \(y=1\). The coordinates of point D are \((0,1)\). -
Name the ordered pair of each point shown:
Ipahayag ang sagot
- A: (4,0)
- B: (0,3)
- C: (−3,0)
- D: (0,−5)
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Name the ordered pair of each point shown:
Ipahayag ang sagot
- A: (−3,0)
- B: (0,−3)
- C: (5,0)
- D: (0,2)
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Determine which ordered pairs are solutions of the equation \(x+4y=8\text{:}\)
- ⓐ \(\ (0,2)\)
- ⓑ \(\ (2,-4)\)
- ⓒ \(\ (-4,3)\)
Ipahayag ang sagot
Substitute the \(x\text{- and}\ y\text{-values}\) from each ordered pair into the equation and determine if the result is a true statement.
ⓐ \(\ (0,2)\) ⓑ \(\ (2,-4)\) ⓒ \(\ (-4,3)\) \((0,2)\) is a solution. \((2,-4)\) is not a solution. \((-4,3)\) is a solution. -
Determine which ordered pairs are solutions to the given equation: \(2x+3y=6\)
- ⓐ \(\ (3,0)\)
- ⓑ \(\ (2,0)\)
- ⓒ \(\ (6,-2)\)
Ipahayag ang sagot
ⓐ , ⓒ
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Determine which ordered pairs are solutions to the given equation: \(4x-y=8\)
- ⓐ \(\ (0,8)\)
- ⓑ \(\ (2,0)\)
- ⓒ \(\ (1,-4)\)
Ipahayag ang sagot
ⓑ , ⓒ
-
Determine which ordered pairs are solutions of the equation. \(y=5x-1\text{:}\)
- ⓐ \(\ (0,-1)\)
- ⓑ \(\ (1,4)\)
- ⓒ \(\ (-2,-7)\)
Ipahayag ang sagot
Substitute the \(x\text{-}\) and \(y\text{-values}\) from each ordered pair into the equation and determine if it results in a true statement.
ⓐ \(\ (0,-1)\) ⓑ \(\ (1,4)\) ⓒ \(\ (-2,-7)\) \((0,-1)\) is a solution. \((1,4)\) is a solution. \((-2,-7)\) is not a solution. -
Determine which ordered pairs are solutions of the given equation: \(y=4x-3\)
- ⓐ \(\ (0,3)\)
- ⓑ \(\ (1,1)\)
- ⓒ \(\ (1,0)\)
Ipahayag ang sagot
ⓑ
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Determine which ordered pairs are solutions of the given equation: \(y=-2x+6\)
- ⓐ \(\ (0,6)\)
- ⓑ \(\ (1,4)\)
- ⓒ \(\ (-2,-2)\)
Ipahayag ang sagot
ⓐ , ⓑ
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Complete the table to find three solutions to the equation \(y=4x-2\text{:}\)
\(y=4x-2\) \(x\) \(y\) \((x,y)\) \(0\) \(-1\) \(2\) Ipahayag ang sagot
Substitute \(x=0,x=-1,\) and \(x=2\) into \(y=4x-2.\)
\(y=4x-2\) \(y=4x-2\) \(y=4x-2\) \(y=0-2\) \(y=-4-2\) \(y=8-2\) \(y=-2\) \(y=-6\) \(y=6\) \((0,-2)\) \((-1,-6)\) \((2,6)\) The results are summarized in the table.
\(y=4x-2\) \(x\) \(y\) \((x,y)\) \(0\) \(-2\) \((0,-2)\) \(-1\) \(-6\) \((-1,-6)\) \(2\) \(6\) \((2,6)\) -
Complete the table to find three solutions to the equation: \(y=3x-1.\)
\(y=3x-1\) \(x\) \(y\) \((x,y)\) \(0\) \(-1\) \(2\) Ipahayag ang sagot
\(y=3x-1\) \(x\) \(y\) \((x,y)\) \(0\) \(-1\) \((0,-1)\) \(-1\) \(-4\) \((-1,-4)\) \(2\) \(5\) \((2,5)\) -
Complete the table to find three solutions to the equation: \(y=6x+1\)
\(y=6x+1\) \(x\) \(y\) \((x,y)\) \(0\) \(1\) \(-2\) Ipahayag ang sagot
\(y=6x+1\) \(x\) \(y\) \((x,y)\) \(0\) \(1\) \((0,1)\) \(1\) \(7\) \((1,7)\) \(-2\) \(-11\) \((-2,-11)\) -
Complete the table to find three solutions to the equation \(5x-4y=20\text{:}\)
\(5x-4y=20\) \(x\) \(y\) \((x,y)\) \(0\) \(0\) \(5\) Ipahayag ang sagot
The results are summarized in the table.
\(5x-4y=20\) \(x\) \(y\) \((x,y)\) \(0\) \(-5\) \((0,-5)\) \(4\) \(0\) \((4,0)\) \(8\) \(5\) \((8,5)\) -
Complete the table to find three solutions to the equation: \(2x-5y=20.\)
\(2x-5y=20\) \(x\) \(y\) \((x,y)\) \(0\) \(0\) \(-5\) Ipahayag ang sagot
\(2x-5y=20\) \(x\) \(y\) \((x,y)\) \(0\) \(-4\) \((0,-4)\) \(10\) \(0\) \((10,0)\) \(-5\) \(-6\) \((-5,-6)\) -
Complete the table to find three solutions to the equation: \(3x-4y=12.\)
\(3x-4y=12\) \(x\) \(y\) \((x,y)\) \(0\) \(0\) \(-4\) Ipahayag ang sagot
\(3x-4y=12\) \(x\) \(y\) \((x,y)\) \(0\) \(-3\) \((0,-3)\) \(4\) \(0\) \((4,0)\) \(-4\) \(-6\) \((-4,-6)\) -
Find a solution to the equation \(3x+2y=6.\)
Ipahayag ang sagot
Step 1: Choose any value for one of the variables in the equation. We can substitute any value we want for \(\ x\\) or any value for \(\ y.\)
Let's pick \(x=0.\)
What is the value of \(\ y\\) if \(\ x=0\)?Step 2: Substitute that value into the equation.
Solve for the other variable.
Substitute \(0\) for \(\ x.\)
Simplify.
Divide both sides by 2.Step 3: Write the solution as an ordered pair. So, when \(x=0,y=3.\) This solution is represented by the ordered pair \((0,3).\) Step 4: Check.
Is the result a true equation?
Yes! -
Find a solution to the equation: \(4x+3y=12.\)
Ipahayag ang sagot
Answers will vary.
-
Find a solution to the equation: \(2x+4y=8.\)
Ipahayag ang sagot
Answers will vary.
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Find three more solutions to the equation \(3x+2y=6.\)
Ipahayag ang sagot
To find solutions to \(3x+2y=6,\) choose a value for \(x\) or \(y.\) Remember, we can choose any value we want for \(x\) or \(y.\) Here we chose \(1\) for \(x,\) and \(0\) and \(-3\) for \(y.\)
Substitute it into the equation. Simplify.
Solve.Write the ordered pair. \((2,0)\) \((1,\frac{3}{2})\) \((4,-3)\) Check your answers.
\((2,0)\) \((1,\frac{3}{2})\) \((4,-3)\) So \((2,0),(1,\frac{3}{2})\) and \((4,-3)\) are all solutions to the equation \(3x+2y=6.\) In the previous example, we found that \((0,3)\) is a solution, too. We can list these solutions in a table.
\(3x+2y=6\) \(x\) \(y\) \((x,y)\) \(0\) \(3\) \((0,3)\) \(2\) \(0\) \((2,0)\) \(1\) \(\frac{3}{2}\) \((1,\frac{3}{2})\) \(4\) \(-3\) \((4,-3)\)
Symbols used here
Both signs at once: x = 3 ± 2 means 5 and 1.
The two sides are different.
Inequalities that allow equality; < and > exclude it.
Equal to the precision shown, not exactly.
The non-negative number whose square (n-th power) is x.
What is left after dividing a by n.
Per hundred: 15% = 15/100.
a for every b; a divided by b.
How to: Use the Rectangular Coordinate System
- Plot points on a rectangular coordinate system
- Identify points on a graph
- Verify solutions to an equation in two variables
- Complete a table of solutions to a linear equation
- Find solutions to linear equations in two variables
- A: (5,1)
- B: (−2,4)
- C: (−5,−1)
Questions people ask
Why does the order of operations matter?
Because 2 + 3 × 4 would otherwise be two different numbers. The convention (brackets, exponents, multiplication and division, addition and subtraction) exists so every reader gets the same value from the same expression.
How do I check an arithmetic answer?
Estimate first (round every number and compute roughly), then compare. If the estimate and the exact answer disagree by more than a little, one of them is wrong. The solver shows every operation, so you can find which line went astray.
Why are fractions harder than decimals?
They are not harder, they are more exact: 1/3 is a precise number, 0.333 is an approximation. Fractions need a common denominator to add, which is the one extra step people trip on.
Subukan ang iyong sarili
Parts of this page are adapted from OpenStax Prealgebra 2e (CC BY-NC-SA 4.0). Condensed and re-explained here; errors are ours.