maths.free › Arithmetic › 11. Graphs › Graphing with Intercepts
Graphing with Intercepts
Identify the intercepts on a graph
Identify the Intercepts on a Graph
Every linear equation has a unique line that represents all the solutions of the equation. When graphing a line by plotting points, each person who graphs the line can choose any three points, so two people graphing the line might use different sets of points.
At first glance, their two lines might appear different since they would have different points labeled. But if all the work was done correctly, the lines will be exactly the same line. One way to recognize that they are indeed the same line is to focus on where the line crosses the axes. Each of these points is called an intercept of the line.
Let’s look at the graph of the lines shown in .
First, notice where each of these lines crosses the x- axis:
| Figure: | The line crosses the x-axis at: | Ordered pair of this point |
| 42 | 3 | (3,0) |
| 43 | 4 | (4,0) |
| 44 | 5 | (5,0) |
| 45 | 0 | (0,0) |
Do you see a pattern?
For each row, the y- coordinate of the point where the line crosses the x- axis is zero. The point where the line crosses the x- axis has the form \((a,0)\); and is called the x-intercept of the line. The x- intercept occurs when y is zero.
Now, let's look at the points where these lines cross the y-axis.
| Figure: | The line crosses the y-axis at: | Ordered pair for this point |
| 42 | 6 | (0,6) |
| 43 | -3 | (0,-3) |
| 44 | -5 | (0,-5) |
| 45 | 0 | (0,0) |
Example
Try it.
Find the \(x\text{- and}\ y\text{-intercepts}\) of each line:
| ⓐ \(\ x+2y=4\) | |
| ⓑ \(\ 3x-y=6\) | |
| ⓒ \(\ x+y=-5\) |
Solution
| ⓐ | |
| The graph crosses the x-axis at the point (4, 0). | The x-intercept is (4, 0). |
| The graph crosses the y-axis at the point (0, 2). | The y-intercept is (0, 2). |
| ⓑ | |
| The graph crosses the x-axis at the point (2, 0). | The x-intercept is (2, 0) |
| The graph crosses the y-axis at the point (0, −6). | The y-intercept is (0, −6). |
| ⓒ | |
| The graph crosses the x-axis at the point (−5, 0). | The x-intercept is (−5, 0). |
| The graph crosses the y-axis at the point (0, −5). | The y-intercept is (0, −5). |
Find the Intercepts from an Equation of a Line
Recognizing that the \(x\text{-intercept}\) occurs when \(y\) is zero and that the \(y\text{-intercept}\) occurs when \(x\) is zero gives us a method to find the intercepts of a line from its equation. To find the \(x\text{-intercept,}\) let \(y=0\) and solve for \(x.\) To find the \(y\text{-intercept},\) let \(x=0\) and solve for \(y.\)
Example
Try it.
Find the intercepts of \(2x+y=6\)
Solution
We'll fill in .
To find the x- intercept, let \(y=0\):
| Substitute 0 for y. | |
| Add. | |
| Divide by 2. | |
| The x-intercept is (3, 0). |
To find the y- intercept, let \(x=0\):
| Substitute 0 for x. | |
| Multiply. | |
| Add. | |
| The y-intercept is (0, 6). |
The intercepts are the points \((3,0)\) and \((0,6)\).
Example
Try it.
Find the intercepts of \(4x-3y=12.\)
Solution
To find the \(x\text{-intercept,}\) let \(y=0.\)
| \(4x-3y=12\) | |
| Substitute 0 for \(y.\) | \(4x-3\cdot 0=12\) |
| Multiply. | \(4x-0=12\) |
| Subtract. | \(4x=12\) |
| Divide by 4. | \(x=3\) |
The \(x\text{-intercept}\) is \((3,0).\)
To find the \(y\text{-intercept},\) let \(x=0.\)
| \(4x-3y=12\) | |
| Substitute 0 for \(x.\) | \(4\cdot 0-3y=12\) |
| Multiply. | \(0-3y=12\) |
| Simplify. | \(-3y=12\) |
| Divide by −3. | \(y=-4\) |
The \(y\text{-intercept}\) is \((0,-4).\)
The intercepts are the points \((-3,0)\) and \((0,-4).\)
| \(4x-3y=12\) | |
| x | y |
| \(3\) | \(0\) |
| \(0\) | \(-4\) |
Graph a Line Using the Intercepts
To graph a linear equation by plotting points, you can use the intercepts as two of your three points. Find the two intercepts, and then a third point to ensure accuracy, and draw the line. This method is often the quickest way to graph a line.
Example
Try it.
Graph \(-x+2y=6\) using intercepts.
Solution
First, find the \(x\text{-intercept}.\) Let \(y=0,\)
\(\begin{array}{l} \\ -x+2y=6 \\ -x+2(0)=6 \\ -x=6 \\ x=-6\end{array}\)
The \(x\text{-intercept}\) is \((-6,0).\)
Now find the \(y\text{-intercept}.\) Let \(x=0.\)
\(\begin{array}{l} \\ -x+2y=6 \\ -0+2y=6 \\ \\ \\ 2y=6 \\ y=3\end{array}\)
The \(y\text{-intercept}\) is \((0,3).\)
Find a third point. We’ll use \(x=2,\)
\(\begin{array}{l} \\ -x+2y=6 \\ -2+2y=6 \\ \\ \\ 2y=8 \\ y=4\end{array}\)
A third solution to the equation is \((2,4).\)
Summarize the three points in a table and then plot them on a graph.
| \(-x+2y=6\) | ||
| x | y | (x,y) |
| \(-6\) | \(0\) | \((-6,0)\) |
| \(0\) | \(3\) | \((0,3)\) |
| \(2\) | \(4\) | \((2,4)\) |
Do the points line up? Yes, so draw line through the points.
Example
Try it.
Graph \(4x-3y=12\) using intercepts.
Solution
Find the intercepts and a third point.
We list the points and show the graph.
| \(4x-3y=12\) | ||
| \(x\) | \(y\) | \((x,y)\) |
| \(3\) | \(0\) | \((3,0)\) |
| \(0\) | \(-4\) | \((0,-4)\) |
| \(6\) | \(4\) | \((6,4)\) |
Example
Try it.
Graph \(y=5x\) using the intercepts.
Solution
This line has only one intercept! It is the point \((0,0).\)
To ensure accuracy, we need to plot three points. Since the intercepts are the same point, we need two more points to graph the line. As always, we can choose any values for \(x,\) so we’ll let \(x\) be \(1\) and \(-1.\)
Organize the points in a table.
| \(y=5x\) | ||
| \(x\) | \(y\) | \((x,y)\) |
| \(0\) | \(0\) | \((0,0)\) |
| \(1\) | \(5\) | \((1,5)\) |
| \(-1\) | \(-5\) | \((-1,-5)\) |
Plot the three points, check that they line up, and draw the line.
Choose the Most Convenient Method to Graph a Line
While we could graph any linear equation by plotting points, it may not always be the most convenient method. This table shows six of equations we’ve graphed in this chapter, and the methods we used to graph them.
| Equation | Method | |
| #1 | \(y=2x+1\) | Plotting points |
| #2 | \(y=\frac{1}{2}x+3\) | Plotting points |
| #3 | \(x=-7\) | Vertical line |
| #4 | \(y=4\) | Horizontal line |
| #5 | \(2x+y=6\) | Intercepts |
| #6 | \(4x-3y=12\) | Intercepts |
What is it about the form of equation that can help us choose the most convenient method to graph its line?
Notice that in equations #1 and #2, y is isolated on one side of the equation, and its coefficient is 1. We found points by substituting values for x on the right side of the equation and then simplifying to get the corresponding y- values.
Equations #3 and #4 each have just one variable. Remember, in this kind of equation the value of that one variable is constant; it does not depend on the value of the other variable. Equations of this form have graphs that are vertical or horizontal lines.
In equations #5 and #6, both x and y are on the same side of the equation. These two equations are of the form \(Ax+By=C\). We substituted \(y=0\) and \(x=0\) to find the x- and y- intercepts, and then found a third point by choosing a value for x or y.
This leads to the following strategy for choosing the most convenient method to graph a line.
Example
Try it.
Identify the most convenient method to graph each line:
- ⓐ \(\ y=-3\\)
- ⓑ \(\ 4x-6y=12\\)
- ⓒ \(\ x=2\\)
- ⓓ \(\ y=\frac{2}{5}x-1\)
Solution
ⓐ \(\ y=-3\)
This equation has only one variable, \(y.\) Its graph is a horizontal line crossing the \(y\text{-axis}\) at \(-3.\)
ⓑ \(\ 4x-6y=12\)
This equation is of the form \(Ax+By=C.\) Find the intercepts and one more point.
ⓒ \(\ x=2\)
There is only one variable, \(x.\) The graph is a vertical line crossing the \(x\text{-axis}\) at \(2.\)
ⓓ \(\ y=\frac{2}{5}x-1\)
Since \(y\) is isolated on the left side of the equation, it will be easiest to graph this line by plotting three points.
Condensed — the full section is in OpenStax Prealgebra 2e.
Key Concepts
- Intercepts
- The x-intercept is the point, \((a,0)\), where the graph crosses the x-axis. The x-intercept occurs when y is zero.
- The y-intercept is the point, \((0,b)\), where the graph crosses the y-axis. The y-intercept occurs when x is zero.
- The x-intercept occurs when y is zero.
- The y-intercept occurs when x is zero.
- Find the x and y intercepts from the equation of a line
- To find the x-intercept of the line, let \(y=0\) and solve for x.
- To find the y-intercept of the line, let \(x=0\) and solve for y.
x y 0 0
- Graph a line using the intercepts
- Find the x- and y- intercepts of the line.
- Let \(y=0\) and solve for x.
- Let \(x=0\) and solve for y.
- Find a third solution to the equation.
- Plot the three points and then check that they line up.
- Draw the line.
- Find the x- and y- intercepts of the line.
- Choose the most convenient method to graph a line
- Determine if the equation has only one variable. Then it is a vertical or horizontal line.
\(x=a\) is a vertical line passing through the x-axis at a.
\(y=b\) is a horizontal line passing through the y-axis at b. - Determine if y is isolated on one side of the equation. The graph by plotting points.
Choose any three values for x and then solve for the corresponding y- values. - Determine if the equation is of the form \(Ax+By=C\), find the intercepts.
Find the x- and y- intercepts and then a third point.
- Determine if the equation has only one variable. Then it is a vertical or horizontal line.
Graphing with Intercepts
Identify the Intercepts on a Graph
In the following exercises, find the \(x\text{-}\) and \(y\text{-}\) intercepts.
Try it.
Solution
(3,0),(0,3)
Try it.
Try it.
Solution
(5,0),(0,−5)
Try it.
Try it.
Solution
(−2,0),(0,−2)
Try it.
Try it.
Solution
(−1,0),(0,1)
Try it.
Try it.
Solution
(0,0)
Try it.
Find the \(x\) and \(y\) Intercepts from an Equation of a Line
In the following exercises, find the intercepts.
Try it.
\(x+y=4\)
Solution
(4,0),(0,4)
Try it.
\(x+y=3\)
Try it.
\(x+y=-2\)
Solution
(−2,0),(0,−2)
Try it.
\(x+y=-5\)
Try it.
\(x-y=5\)
Solution
(5,0),(0,−5)
Try it.
\(x-y=1\)
Try it.
\(x-y=-3\)
Solution
(−3,0),(0,3)
Try it.
\(x-y=-4\)
Try it.
\(x+2y=8\)
Solution
(8,0),(0,4)
Try it.
\(x+2y=10\)
Try it.
\(3x+y=6\)
Solution
(2,0),(0,6)
Try it.
\(3x+y=9\)
Try it.
\(x-3y=12\)
Solution
(12,0),(0,−4)
Try it.
\(x-2y=8\)
Try it.
\(4x-y=8\)
Solution
(2,0),(0,−8)
Try it.
\(5x-y=5\)
Try it.
\(2x+5y=10\)
Solution
(5,0),(0,2)
Try it.
\(2x+3y=6\)
Try it.
\(3x-2y=12\)
Solution
(4,0),(0,−6)
Try it.
\(3x-5y=30\)
Try it.
\(y=\frac{1}{3}x-1\)
Solution
(3,0),(0,−1)
Try it.
\(y=\frac{1}{4}x-1\)
Try it.
\(y=\frac{1}{5}x+2\)
Solution
(−10,0),(0,2)
Try it.
\(y=\frac{1}{3}x+4\)
Try it.
\(y=3x\)
Solution
(0,0)
Try it.
\(y=-2x\)
Try it.
\(y=-4x\)
Solution
(0,0)
Try it.
\(y=5x\)
Graph a Line Using the Intercepts
In the following exercises, graph using the intercepts.
Try it.
\(-x+5y=10\)
Solution
Try it.
\(-x+4y=8\)
Try it.
\(x+2y=4\)
Solution
Try it.
\(x+2y=6\)
Try it.
\(x+y=2\)
Solution
Try it.
\(x+y=5\)
Try it.
\(x+y=3\)
Solution
Try it.
\(x+y=-1\)
Try it.
\(x-y=1\)
Solution
Try it.
\(x-y=2\)
Try it.
\(x-y=-4\)
Solution
Try it.
\(x-y=-3\)
Try it.
\(4x+y=4\)
Solution
Try it.
\(3x+y=3\)
Try it.
\(3x-y=-6\)
Solution
Try it.
\(2x-y=-8\)
Try it.
\(2x+4y=12\)
Solution
Try it.
\(3x+2y=12\)
Try it.
\(3x-2y=6\)
Solution
Try it.
\(5x-2y=10\)
Try it.
\(2x-5y=-20\)
Solution
Try it.
\(3x-4y=-12\)
Try it.
\(y=-2x\)
Solution
Try it.
\(y=-4x\)
Try it.
\(y=x\)
Solution
Try it.
\(y=3x\)
Choose the Most Convenient Method to Graph a Line
In the following exercises, identify the most convenient method to graph each line.
Try it.
\(x=2\)
Solution
vertical line
Try it.
\(y=4\)
Try it.
\(y=5\)
Solution
horizontal line
Try it.
\(x=-3\)
Try it.
\(y=-3x+4\)
Solution
plotting points
Try it.
\(y=-5x+2\)
Try it.
\(x-y=5\)
Solution
intercepts
Try it.
\(x-y=1\)
Try it.
\(y=\frac{2}{3}x-1\)
Solution
plotting points
Try it.
\(y=\frac{4}{5}x-3\)
Try it.
\(y=-3\)
Solution
horizontal line
Try it.
\(y=-1\)
Try it.
\(3x-2y=-12\)
Solution
intercepts
Try it.
\(2x-5y=-10\)
Try it.
\(y=-\frac{1}{4}x+3\)
Solution
plotting points
Try it.
\(y=-\frac{1}{3}x+5\)
Try it.
How do you find the \(x\text{-intercept}\) of the graph of \(3x-2y=6?\)
Solution
Answers will vary.
Try it.
How do you find the \(y\text{-intercept}\) of the graph of \(5x-y=10?\)
Try it.
Do you prefer to graph the equation \(4x+y=-4\) by plotting points or intercepts? Why?
Solution
Answers will vary.
Try it.
Do you prefer to graph the equation \(y=\frac{2}{3}x-2\) by plotting points or intercepts? Why?
Condensed — the full section is in OpenStax Prealgebra 2e.
Practice (40)
Try each one on paper first. Reveal the answer to check; verified ones can be opened in the solver for every step.
-
Solve: \(3x+4y=-12\) for \(x\) when \(y=0.\)
If you missed this problem, review .גלה את התשובה
\(-4\)
-
Is the point \((0,-5)\) on the \(x\text{-axis}\) or \(y\text{-axis?}\)
If you missed this problem, review .גלה את התשובה
\(y\text{-axis}\)
-
Which ordered pairs are solutions to the equation \(2x-y=6?\)
ⓐ \(\ (6,0)\\)ⓑ \(\ (0,-6)\\)ⓒ \(\ (4,-2).\)
If you missed this problem, review .גלה את התשובה
b
-
Find the \(x\text{- and}\ y\text{-intercepts}\) of each line:
ⓐ \(\ x+2y=4\) ⓑ \(\ 3x-y=6\) ⓒ \(\ x+y=-5\) גלה את התשובה
ⓐ The graph crosses the x-axis at the point (4, 0). The x-intercept is (4, 0). The graph crosses the y-axis at the point (0, 2). The y-intercept is (0, 2). ⓑ The graph crosses the x-axis at the point (2, 0). The x-intercept is (2, 0) The graph crosses the y-axis at the point (0, −6). The y-intercept is (0, −6). ⓒ The graph crosses the x-axis at the point (−5, 0). The x-intercept is (−5, 0). The graph crosses the y-axis at the point (0, −5). The y-intercept is (0, −5). -
Find the \(x\text{-}\) and \(y\text{-intercepts}\) of the graph: \(x-y=2.\)
גלה את התשובה
x-intercept (2,0): y-intercept (0,−2)
-
Find the \(x\text{-}\) and \(y\text{-intercepts}\) of the graph: \(2x+3y=6.\)
גלה את התשובה
x-intercept (3,0); y-intercept (0,2)
-
Find the intercepts of \(2x+y=6\)
גלה את התשובה
We'll fill in .
To find the x- intercept, let \(y=0\):
Substitute 0 for y. Add. Divide by 2. The x-intercept is (3, 0). To find the y- intercept, let \(x=0\):
Substitute 0 for x. Multiply. Add. The y-intercept is (0, 6). The intercepts are the points \((3,0)\) and \((0,6)\).
-
Find the intercepts: \(3x+y=12\)
גלה את התשובה
\((4,0)\) and \((0,12)\)
-
Find the intercepts: \(x+4y=8\)
גלה את התשובה
\((8,0)\) and \((0,2)\)
-
Find the intercepts of \(4x-3y=12.\)
גלה את התשובה
To find the \(x\text{-intercept,}\) let \(y=0.\)
\(4x-3y=12\) Substitute 0 for \(y.\) \(4x-3\cdot 0=12\) Multiply. \(4x-0=12\) Subtract. \(4x=12\) Divide by 4. \(x=3\) The \(x\text{-intercept}\) is \((3,0).\)
To find the \(y\text{-intercept},\) let \(x=0.\)
\(4x-3y=12\) Substitute 0 for \(x.\) \(4\cdot 0-3y=12\) Multiply. \(0-3y=12\) Simplify. \(-3y=12\) Divide by −3. \(y=-4\) The \(y\text{-intercept}\) is \((0,-4).\)
The intercepts are the points \((-3,0)\) and \((0,-4).\)
\(4x-3y=12\) x y \(3\) \(0\) \(0\) \(-4\) -
Find the intercepts of the line: \(3x-4y=12.\)
גלה את התשובה
x-intercept (4,0); y-intercept: (0,−3)
-
Find the intercepts of the line: \(2x-4y=8.\)
גלה את התשובה
x-intercept (4,0); y-intercept: (0,−2)
-
Graph \(-x+2y=6\) using intercepts.
גלה את התשובה
First, find the \(x\text{-intercept}.\) Let \(y=0,\)
\(\begin{array}{l} \\ -x+2y=6 \\ -x+2(0)=6 \\ -x=6 \\ x=-6\end{array}\)
The \(x\text{-intercept}\) is \((-6,0).\)
Now find the \(y\text{-intercept}.\) Let \(x=0.\)
\(\begin{array}{l} \\ -x+2y=6 \\ -0+2y=6 \\ \\ \\ 2y=6 \\ y=3\end{array}\)
The \(y\text{-intercept}\) is \((0,3).\)
Find a third point. We’ll use \(x=2,\)
\(\begin{array}{l} \\ -x+2y=6 \\ -2+2y=6 \\ \\ \\ 2y=8 \\ y=4\end{array}\)
A third solution to the equation is \((2,4).\)
Summarize the three points in a table and then plot them on a graph.
\(-x+2y=6\) x y (x,y) \(-6\) \(0\) \((-6,0)\) \(0\) \(3\) \((0,3)\) \(2\) \(4\) \((2,4)\) Do the points line up? Yes, so draw line through the points.
-
Graph the line using the intercepts: \(x-2y=4.\)
גלה את התשובה
-
Graph the line using the intercepts: \(-x+3y=6.\)
גלה את התשובה
-
Graph \(4x-3y=12\) using intercepts.
גלה את התשובה
Find the intercepts and a third point.
We list the points and show the graph.
\(4x-3y=12\) \(x\) \(y\) \((x,y)\) \(3\) \(0\) \((3,0)\) \(0\) \(-4\) \((0,-4)\) \(6\) \(4\) \((6,4)\) -
Graph the line using the intercepts: \(5x-2y=10.\)
גלה את התשובה
-
Graph the line using the intercepts: \(3x-4y=12.\)
גלה את התשובה
-
Graph \(y=5x\) using the intercepts.
גלה את התשובה
This line has only one intercept! It is the point \((0,0).\)
To ensure accuracy, we need to plot three points. Since the intercepts are the same point, we need two more points to graph the line. As always, we can choose any values for \(x,\) so we’ll let \(x\) be \(1\) and \(-1.\)
Organize the points in a table.
\(y=5x\) \(x\) \(y\) \((x,y)\) \(0\) \(0\) \((0,0)\) \(1\) \(5\) \((1,5)\) \(-1\) \(-5\) \((-1,-5)\) Plot the three points, check that they line up, and draw the line.
-
Graph using the intercepts: \(y=4x.\)
גלה את התשובה
-
Graph using the intercepts: \(y=-x.\)
גלה את התשובה
-
Identify the most convenient method to graph each line:
- ⓐ \(\ y=-3\\)
- ⓑ \(\ 4x-6y=12\\)
- ⓒ \(\ x=2\\)
- ⓓ \(\ y=\frac{2}{5}x-1\)
גלה את התשובה
ⓐ \(\ y=-3\)
This equation has only one variable, \(y.\) Its graph is a horizontal line crossing the \(y\text{-axis}\) at \(-3.\)
ⓑ \(\ 4x-6y=12\)
This equation is of the form \(Ax+By=C.\) Find the intercepts and one more point.
ⓒ \(\ x=2\)
There is only one variable, \(x.\) The graph is a vertical line crossing the \(x\text{-axis}\) at \(2.\)
ⓓ \(\ y=\frac{2}{5}x-1\)
Since \(y\) is isolated on the left side of the equation, it will be easiest to graph this line by plotting three points.
-
Identify the most convenient method to graph each line:
- ⓐ \(\ 3x+2y=12\)
- ⓑ \(\ y=4\)
- ⓒ \(\ y=\frac{1}{5}x-4\)
- ⓓ \(\ x=-7\)
גלה את התשובה
- ⓐ intercepts
- ⓑ horizontal line
- ⓒ plotting points
- ⓓ vertical line
-
Identify the most convenient method to graph each line:
- ⓐ \(\ x=6\)
- ⓑ \(\ y=-\frac{3}{4}x+1\)
- ⓒ \(\ y=-8\)
- ⓓ \(\ 4x-3y=-1\)
גלה את התשובה
- ⓐ vertical line
- ⓑ plotting points
- ⓒ horizontal line
- ⓓ intercepts
-
\(2x+5y=10\)
גלה את התשובה
(5,0),(0,2)
-
\(3x-2y=12\)
גלה את התשובה
(4,0),(0,−6)
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\(3x-5y=30\)
-
\(y=\frac{1}{3}x-1\)
גלה את התשובה
(3,0),(0,−1)
-
\(y=\frac{1}{4}x-1\)
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\(y=\frac{1}{5}x+2\)
גלה את התשובה
(−10,0),(0,2)
-
\(y=\frac{1}{3}x+4\)
-
\(-x+5y=10\)
גלה את התשובה
-
\(2x+4y=12\)
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\(3x+2y=12\)
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\(5x-2y=10\)
-
\(2x-5y=-20\)
גלה את התשובה
-
\(3x-4y=-12\)
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\(y=\frac{2}{3}x-1\)
גלה את התשובה
plotting points
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\(y=\frac{4}{5}x-3\)
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\(3x-2y=-12\)
גלה את התשובה
intercepts
Symbols used here
Both signs at once: x = 3 ± 2 means 5 and 1.
The two sides are different.
Inequalities that allow equality; < and > exclude it.
Equal to the precision shown, not exactly.
The non-negative number whose square (n-th power) is x.
What is left after dividing a by n.
Per hundred: 15% = 15/100.
a for every b; a divided by b.
How to: Graphing with Intercepts
- Identify the intercepts on a graph
- Find the intercepts from an equation of a line
- Graph a line using the intercepts
- Choose the most convenient method to graph a line
- the
- the
- Find the
- Let
Questions people ask
Why does the order of operations matter?
Because 2 + 3 × 4 would otherwise be two different numbers. The convention (brackets, exponents, multiplication and division, addition and subtraction) exists so every reader gets the same value from the same expression.
How do I check an arithmetic answer?
Estimate first (round every number and compute roughly), then compare. If the estimate and the exact answer disagree by more than a little, one of them is wrong. The solver shows every operation, so you can find which line went astray.
Why are fractions harder than decimals?
They are not harder, they are more exact: 1/3 is a precise number, 0.333 is an approximation. Fractions need a common denominator to add, which is the one extra step people trip on.
נסה את שלך.
Parts of this page are adapted from OpenStax Prealgebra 2e (CC BY-NC-SA 4.0). Condensed and re-explained here; errors are ours.