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Commutative and Associative Properties

Use the commutative and associative properties

Use the Commutative and Associative Properties

Think about adding two numbers, such as \(5\) and \(3.\)

\[\begin{array}{llll}5+3 & & & 3+5 \\ 8 & & & 8\end{array}\]

The results are the same. \(5+3=3+5\)

Notice, the order in which we add does not matter. The same is true when multiplying \(5\) and \(3.\)

\[\begin{array}{llll}5\cdot 3 & & & 3\cdot 5 \\ 15 & & & 15\end{array}\]

Again, the results are the same! \(5\cdot 3=3\cdot 5.\) The order in which we multiply does not matter.

These examples illustrate the commutative properties of addition and multiplication.

The commutative properties have to do with order. If you change the order of the numbers when adding or multiplying, the result is the same.

Example

Try it.

Use the commutative properties to rewrite the following expressions:

  1. ⓐ \(\ -1+3=_____\)

  2. ⓑ \(\ 4\cdot 9=_____\)

Solution
ⓐ
\(-1+3=_____\)
Use the commutative property of addition to change the order.\(-1+3=3+(-1)\)
ⓑ
\(4\cdot 9=_____\)
Use the commutative property of multiplication to change the order.\(4\cdot 9=9\cdot 4\)

What about subtraction? Does order matter when we subtract numbers? Does \(7-3\) give the same result as \(3-7?\)

\[\begin{array}{lll}7-3 & & 3-7 \\ 4 & & -4 \\ & 4\ne -4 & \end{array}\]\[\text{The results are not the same.}\ 7-3\ne 3-7\]\[\begin{array}{lll}12\div 4 & & 4\div 12 \\ \frac{12}{4} & & \frac{4}{12} \\ 3 & & \frac{1}{3} \\ & 3\ne \frac{1}{3} & \end{array}\]\[\text{The results are not the same. So}\ 12\div 4\ne 4\div 12\]\[7+8+2\]\[5\cdot \frac{1}{3}\cdot 3\]

Condensed — the full section is in OpenStax Prealgebra 2e.

Evaluate Expressions using the Commutative and Associative Properties

The commutative and associative properties can make it easier to evaluate some algebraic expressions. Since order does not matter when adding or multiplying three or more terms, we can rearrange and re-group terms to make our work easier, as the next several examples illustrate.

Example

Try it.

Evaluate each expression when \(x=\frac{7}{8}.\)

  1. ⓐ \(\ x+0.37+(-x)\)
  2. ⓑ \(\ x+(-x)+0.37\)
Solution
ⓐ
Substitute \(\frac{7}{8}\) for \(x\).
Convert fractions to decimals.
Add left to right.
Subtract.
ⓑ
Substitute \(\frac{7}{8}\) for x.
Add opposites first.

What was the difference between part ⓐ and part ⓑ ? Only the order changed. By the Commutative Property of Addition, \(x+0.37+(-x)=x+(-x)+0.37.\) But wasn’t part ⓑ much easier?

Let’s do one more, this time with multiplication.

Example

Try it.

Evaluate each expression when \(n=17.\)

  1. ⓐ \(\ \frac{4}{3}(\frac{3}{4}n)\)

  2. ⓑ \(\ (\frac{4}{3}\cdot \frac{3}{4})n\)

Solution
ⓐ
Substitute 17 for n.
Multiply in the parentheses first.
Multiply again.
ⓑ
Substitute 17 for n.
Multiply. The product of reciprocals is 1.
Multiply again.

What was the difference between part ⓐ and part ⓑ here? Only the grouping changed. By the Associative Property of Multiplication, \(\frac{4}{3}(\frac{3}{4}n)=(\frac{4}{3}\cdot \frac{3}{4})n.\) By carefully choosing how to group the factors, we can make the work easier.

Simplify Expressions Using the Commutative and Associative Properties

When we have to simplify algebraic expressions, we can often make the work easier by applying the Commutative or Associative Property first instead of automatically following the order of operations. Notice that in part ⓑ was easier to simplify than part ⓐ because the opposites were next to each other and their sum is \(0.\) Likewise, part ⓑ in was easier, with the reciprocals grouped together, because their product is \(1.\) In the next few examples, we’ll use our number sense to look for ways to apply these properties to make our work easier.

Example

Try it.

Simplify: \(-84n+(-73n)+84n.\)

Solution

Notice the first and third terms are opposites, so we can use the commutative property of addition to reorder the terms.

\(-84n+(-73n)+84n\)
Re-order the terms.\(-84n+84n+(-73n)\)
Add left to right.\(0+(-73n)\)
Add.\(-73n\)

Now we will see how recognizing reciprocals is helpful. Before multiplying left to right, look for reciprocals—their product is \(1.\)

Example

Try it.

Simplify: \(\frac{7}{15}\cdot \frac{8}{23}\cdot \frac{15}{7}.\)

Solution

Notice the first and third terms are reciprocals, so we can use the Commutative Property of Multiplication to reorder the factors.

\(\frac{7}{15}\cdot \frac{8}{23}\cdot \frac{15}{7}\)
Re-order the terms.\(\frac{7}{15}\cdot \frac{15}{7}\cdot \frac{8}{23}\)
Multiply left to right.\(1\cdot \frac{8}{23}\)
Multiply.\(\frac{8}{23}\)

In expressions where we need to add or subtract three or more fractions, combine those with a common denominator first.

Example

Try it.

Simplify: \((\frac{5}{13}+\frac{3}{4})+\frac{1}{4}.\)

Solution

Notice that the second and third terms have a common denominator, so this work will be easier if we change the grouping.

\((\frac{5}{13}+\frac{3}{4})+\frac{1}{4}\)
Group the terms with a common denominator.\(\frac{5}{13}+(\frac{3}{4}+\frac{1}{4})\)
Add in the parentheses first.\(\frac{5}{13}+(\frac{4}{4})\)
Simplify the fraction.\(\frac{5}{13}+1\)
Add.\(1\frac{5}{13}\)
Convert to an improper fraction.\(\frac{18}{13}\)

When adding and subtracting three or more terms involving decimals, look for terms that combine to give whole numbers.

Condensed — the full section is in OpenStax Prealgebra 2e.

Key Concepts

  • Commutative Properties
    • Commutative Property of Addition:
      • If \(a,b\) are real numbers, then \(a+b=b+a\)
    • Commutative Property of Multiplication:
      • If \(a,b\) are real numbers, then \(a⋅b=b⋅a\)
  • Associative Properties
    • Associative Property of Addition:
      • If \(a,b,c\) are real numbers then \((a+b)+c=a+(b+c)\)
    • Associative Property of Multiplication:
      • If \(a,b,c\) are real numbers then \((a⋅b)⋅c=a⋅(b⋅c)\)

Commutative and Associative Properties

Use the Commutative and Associative Properties

In the following exercises, use the commutative properties to rewrite the given expression.

Try it.

\(8+9=___\)

Try it.

\(7+6=___\)

Solution

7 + 6 = 6 + 7

Try it.

\(8(-12)=___\)

Try it.

\(7(-13)=___\)

Solution

7(−13) = (−13)7

Try it.

\((-19)(-14)=___\)

Try it.

\((-12)(-18)=___\)

Solution

(−12)(−18) = (−18)(−12)

Try it.

\(-11+8=___\)

Try it.

\(-15+7=___\)

Solution

−15 + 7 = 7 + (−15)

Try it.

\(x+4=___\)

Try it.

\(y+1=___\)

Solution

y + 1 = 1 + y

Try it.

\(-2a=___\)

Try it.

\(-3m=___\)

Solution

−3m = m(−3)

In the following exercises, use the associative properties to rewrite the given expression.

Try it.

\((11+9)+14=___\)

Try it.

\((21+14)+9=___\)

Solution

(21 + 14) + 9 = 21 + (14 + 9)

Try it.

\((12\cdot 5)\cdot 7=___\)

Try it.

\((14\cdot 6)\cdot 9=___\)

Solution

(14 · 6) · 9 = 14(6 · 9)

Try it.

\((-7+9)+8=___\)

Try it.

\((-2+6)+7=___\)

Solution

(−2 + 6) + 7 = −2 + (6 + 7)

Try it.

\((16\cdot \frac{4}{5})\cdot 15=___\)

Try it.

\((13\cdot \frac{2}{3})\cdot 18=___\)

Solution

\((13\cdot \frac{2}{3})\cdot 18=13(\frac{2}{3}\cdot 18)\)

Try it.

\(3(4x)=___\)

Try it.

\(4(7x)=___\)

Solution

4(7x) = (4 · 7)x

Try it.

\((12+x)+28=___\)

Try it.

\((17+y)+33=___\)

Solution

(17 + y) + 33 = 17 + (y + 33)

Evaluate Expressions using the Commutative and Associative Properties

In the following exercises, evaluate each expression for the given value.

Try it.

If \(y=\frac{5}{8},\) evaluate:

  1. ⓐ \(\ y+0.49+(-y)\)
  2. ⓑ \(\ y+(-y)+0.49\)

Try it.

If \(z=\frac{7}{8},\) evaluate:

  • ⓐ \(\ z+0.97+(-z)\)
  • ⓑ \(\ z+(-z)+0.97\)

Solution
  1. ⓐ 0.97
  2. ⓑ 0.97

Try it.

If \(c=-\frac{11}{4},\) evaluate:

  1. ⓐ \(\ c+3.125+(-c)\)
  2. ⓑ \(\ c+(-c)+3.125\)

Try it.

If \(d=-\frac{9}{4},\) evaluate:

  1. ⓐ \(\ d+2.375+(-d)\)
  2. ⓑ \(\ d+(-d)+2.375\)

Solution

  1. ⓐ 2.375
  2. ⓑ 2.375

Try it.

If \(j=11,\) evaluate:

  1. ⓐ \(\ \frac{5}{6}(\frac{6}{5}j)\)
  2. ⓑ \(\ (\frac{5}{6}\cdot \frac{6}{5})j\)

Try it.

If \(k=21,\) evaluate:

  1. ⓐ \(\ \frac{4}{13}(\frac{13}{4}k)\)
  2. ⓑ \(\ (\frac{4}{13}\cdot \frac{13}{4})k\)

Solution

  1. ⓐ 21
  2. ⓑ 21

Try it.

If \(m=-25,\) evaluate:

  1. ⓐ \(\ -\frac{3}{7}(\frac{7}{3}m)\)
  2. ⓑ \(\ (-\frac{3}{7}\cdot \frac{7}{3})m\)

Try it.

If \(n=-8,\) evaluate:

  1. ⓐ \(\ -\frac{5}{21}(\frac{21}{5}n)\)
  2. ⓑ \(\ (-\frac{5}{21}\cdot \frac{21}{5})n\)

Solution

  1. ⓐ 8
  2. ⓑ 8

Simplify Expressions Using the Commutative and Associative Properties

In the following exercises, simplify.

Try it.

\(-45a+15+45a\)

Try it.

\(9y+23+(-9y)\)

Solution

23

Try it.

\(\frac{1}{2}+\frac{7}{8}+(-\frac{1}{2})\)

Try it.

\(\frac{2}{5}+\frac{5}{12}+(-\frac{2}{5})\)

Solution

\(\frac{5}{12}\)

Try it.

\(\frac{3}{20}\cdot \frac{49}{11}\cdot \frac{20}{3}\)

Try it.

\(\frac{13}{18}\cdot \frac{25}{7}\cdot \frac{18}{13}\)


Solution

\(\frac{25}{7}\)

Try it.

\(\frac{7}{12}\cdot \frac{9}{17}\cdot \frac{24}{7}\)

Try it.

\(\frac{3}{10}\cdot \frac{13}{23}\cdot \frac{50}{3}\)

Solution

\(\frac{65}{23}\)

Try it.

\(-24\cdot 7\cdot \frac{3}{8}\)

Try it.

\(-36\cdot 11\cdot \frac{4}{9}\)

Solution

−176

Try it.

\((\frac{5}{6}+\frac{8}{15})+\frac{7}{15}\)

Try it.

\((\frac{1}{12}+\frac{4}{9})+\frac{5}{9}\)

Solution

\(\frac{13}{12}\)

Try it.

\(\frac{5}{13}+\frac{3}{4}+\frac{1}{4}\)

Try it.

\(\frac{8}{15}+\frac{5}{7}+\frac{2}{7}\)

Solution

\(\frac{23}{15}\)

Try it.

\((4.33p+1.09p)+3.91p\)

Try it.

\((5.89d+2.75d)+1.25d\)

Solution

9.89d

Try it.

\(17(0.25)(4)\)

Try it.

\(36(0.2)(5)\)

Solution

36

Try it.

\([2.48(12)](0.5)\)

Try it.

\([9.731(4)](0.75)\)

Solution

29.193

Try it.

\(7(4a)\)

Try it.

\(9(8w)\)

Solution

72w

Try it.

\(-15(5m)\)

Try it.

\(-23(2n)\)

Solution

−46n

Try it.

\(12(\frac{5}{6}p)\)

Try it.

\(20(\frac{3}{5}q)\)

Solution

12q

Try it.

\(14x+19y+25x+3y\)

Try it.

\(15u+11v+27u+19v\)

Solution

42u + 30v

Try it.

\(43m+(-12n)+\text{}(-16m)+(-9n)\)

Try it.

\(-22p+17q+(-35p)+(-27q)\)

Solution

−57p + (−10q)

Try it.

\(\frac{3}{8}g+\frac{1}{12}h+\frac{7}{8}g+\frac{5}{12}h\)

Try it.

\(\frac{5}{6}a+\frac{3}{10}b+\frac{1}{6}a+\frac{9}{10}b\)

Solution

\(a+\frac{6}{5}b\)

Try it.

\(6.8p+9.14q+(-4.37p)+(-0.88q)\)

Try it.

\(9.6m+7.22n+(-2.19m)+(-0.65n)\)

Solution

7.41m + 6.57n

Condensed — the full section is in OpenStax Prealgebra 2e.

Practice (40)

Try each one on paper first. Reveal the answer to check; verified ones can be opened in the solver for every step.

  1. Simplify: \(7y+2+y+13.\)
    If you missed this problem, review .

    جواب کھوليں

    \(8y+15\)

  2. Multiply: \(\frac{2}{3}\cdot 18.\)
    If you missed this problem, review .

    جواب کھوليں

    \(12\)

  3. Find the opposite of \(15.\)
    If you missed this problem, review .

    جواب کھوليں

    \(-15\)

  4. Use the commutative properties to rewrite the following expressions:

    1. ⓐ \(\ -1+3=_____\)

    2. ⓑ \(\ 4\cdot 9=_____\)

    جواب کھوليں
    ⓐ
    \(-1+3=_____\)
    Use the commutative property of addition to change the order.\(-1+3=3+(-1)\)
    ⓑ
    \(4\cdot 9=_____\)
    Use the commutative property of multiplication to change the order.\(4\cdot 9=9\cdot 4\)

  5. Use the commutative properties to rewrite the following:

    1. ⓐ \(\ -4+7=_____\\)
    2. ⓑ \(\ 6\cdot 12=_____\)

    جواب کھوليں
    1. ⓐ −4 + 7 = 7 + (−4)
    2. ⓑ 6 · 12 = 12 · 6

  6. Use the commutative properties to rewrite the following:

    1. ⓐ \(\ 14+(-2)=_____\\)
    2. ⓑ \(\ 3(-5)=_____\)

    جواب کھوليں
    1. ⓐ 14 + (−2) = −2 + 14
    2. ⓑ 3(−5) = (−5)3

  7. Use the associative properties to rewrite the following:

    1. ⓐ \(\ (3+0.6)+0.4=__________\)

    2. ⓑ \(\ (-4\cdot \frac{2}{5})\cdot 15=__________\)

    جواب کھوليں
    ⓐ
    \((3+0.6)+0.4=__________\)
    Change the grouping.\((3+0.6)+0.4=3+(0.6+0.4)\)

    Notice that \(0.6+0.4\) is \(1,\) so the addition will be easier if we group as shown on the right.

    ⓑ
    \((-4\cdot \frac{2}{5})\cdot 15=__________\)
    Change the grouping.\((-4\cdot \frac{2}{5})\cdot 15=-4\cdot (\frac{2}{5}\cdot 15)\)

    Notice that \(\frac{2}{5}\cdot 15\) is \(6.\) The multiplication will be easier if we group as shown on the right.

  8. Use the associative properties to rewrite the following:
    ⓐ \((1+0.7)+0.3=__________\\) ⓑ \(\ (-9\cdot 8)\cdot \frac{3}{4}=__________\)

    جواب کھوليں
    1. ⓐ \(\ (1+0.7)+0.3=1+(0.7+0.3)\)
    2. ⓑ \(\ (-9\cdot 8)\cdot \frac{3}{4}=-9(8\cdot \frac{3}{4})\)

  9. Use the associative properties to rewrite the following:
    ⓐ \((4+0.6)+0.4=__________\\) ⓑ \(\ (-2\cdot 12)\cdot \frac{5}{6}=__________\)

    جواب کھوليں
    1. ⓐ \(\ (4+0.6)+0.4=4+(0.6+0.4)\)
    2. ⓑ \(\ (-2\cdot 12)\cdot \frac{5}{6}=-2(12\cdot \frac{5}{6})\)

  10. Use the Associative Property of Multiplication to simplify: \(6(3x).\)

    جواب کھوليں
    \(6(3x)\)
    Change the grouping.\((6\cdot 3)x\)
    Multiply in the parentheses.\(18x\)

    Notice that we can multiply \(6\cdot 3,\) but we could not multiply \(3\cdot x\) without having a value for \(x.\)

  11. Use the Associative Property of Multiplication to simplify the given expression: \(8(4x).\)

    جواب کھوليں

    8(4x) = (8 · 4)x = 32x

  12. Use the Associative Property of Multiplication to simplify the given expression: \(-9(7y).\)

    جواب کھوليں

    −9(7y) = (−9 · 7)y = −63y

  13. Evaluate each expression when \(x=\frac{7}{8}.\)

    1. ⓐ \(\ x+0.37+(-x)\)
    2. ⓑ \(\ x+(-x)+0.37\)
    جواب کھوليں
    ⓐ
    Substitute \(\frac{7}{8}\) for \(x\).
    Convert fractions to decimals.
    Add left to right.
    Subtract.
    ⓑ
    Substitute \(\frac{7}{8}\) for x.
    Add opposites first.

    What was the difference between part ⓐ and part ⓑ ? Only the order changed. By the Commutative Property of Addition, \(x+0.37+(-x)=x+(-x)+0.37.\) But wasn’t part ⓑ much easier?

  14. Evaluate each expression when \(y=\frac{3}{8}:\\)ⓐ \(\ y+0.84+(-y)\) ⓑ \(\ y+(-y)+0.84.\)

    جواب کھوليں

    1. ⓐ 0.84
    2. ⓑ 0.84

  15. Evaluate each expression when \(f=\frac{17}{20}:\\)ⓐ \(\ f+0.975+(-f)\) ⓑ \(\ f+(-f)+0.975.\)

    جواب کھوليں

    1. ⓐ 0.975
    2. ⓑ 0.975

  16. Evaluate each expression when \(n=17.\)

    1. ⓐ \(\ \frac{4}{3}(\frac{3}{4}n)\)

    2. ⓑ \(\ (\frac{4}{3}\cdot \frac{3}{4})n\)

    جواب کھوليں
    ⓐ
    Substitute 17 for n.
    Multiply in the parentheses first.
    Multiply again.
    ⓑ
    Substitute 17 for n.
    Multiply. The product of reciprocals is 1.
    Multiply again.

    What was the difference between part ⓐ and part ⓑ here? Only the grouping changed. By the Associative Property of Multiplication, \(\frac{4}{3}(\frac{3}{4}n)=(\frac{4}{3}\cdot \frac{3}{4})n.\) By carefully choosing how to group the factors, we can make the work easier.

  17. Evaluate each expression when \(p=24\text{:}\\)ⓐ \(\ \frac{5}{9}(\frac{9}{5}p)\\) ⓑ \(\ (\frac{5}{9}\cdot \frac{9}{5})p.\)

    جواب کھوليں

    1. ⓐ 24
    2. ⓑ 24

  18. Evaluate each expression when \(q=15\text{:}\\)ⓐ \(\ \frac{7}{11}(\frac{11}{7}q)\\) ⓑ \(\ (\frac{7}{11}\cdot \frac{11}{7})q\)

    جواب کھوليں

    1. ⓐ 15
    2. ⓑ 15

  19. Simplify: \(-84n+(-73n)+84n.\)

    جواب کھوليں

    Notice the first and third terms are opposites, so we can use the commutative property of addition to reorder the terms.

    \(-84n+(-73n)+84n\)
    Re-order the terms.\(-84n+84n+(-73n)\)
    Add left to right.\(0+(-73n)\)
    Add.\(-73n\)

  20. Simplify: \(-27a+(-48a)+27a.\)

    جواب کھوليں

    −48a

  21. Simplify: \(39x+(-92x)+(-39x).\)

    جواب کھوليں

    −92x

  22. Simplify: \(\frac{7}{15}\cdot \frac{8}{23}\cdot \frac{15}{7}.\)

    جواب کھوليں

    Notice the first and third terms are reciprocals, so we can use the Commutative Property of Multiplication to reorder the factors.

    \(\frac{7}{15}\cdot \frac{8}{23}\cdot \frac{15}{7}\)
    Re-order the terms.\(\frac{7}{15}\cdot \frac{15}{7}\cdot \frac{8}{23}\)
    Multiply left to right.\(1\cdot \frac{8}{23}\)
    Multiply.\(\frac{8}{23}\)

  23. Simplify: \(\frac{9}{16}\cdot \frac{5}{49}\cdot \frac{16}{9}.\)

    جواب کھوليں

    \(\frac{5}{49}\)

  24. Simplify: \(\frac{6}{17}\cdot \frac{11}{25}\cdot \frac{17}{6}.\)

    جواب کھوليں

    \(\frac{11}{25}\)

  25. Simplify: \((\frac{5}{13}+\frac{3}{4})+\frac{1}{4}.\)

    جواب کھوليں

    Notice that the second and third terms have a common denominator, so this work will be easier if we change the grouping.

    \((\frac{5}{13}+\frac{3}{4})+\frac{1}{4}\)
    Group the terms with a common denominator.\(\frac{5}{13}+(\frac{3}{4}+\frac{1}{4})\)
    Add in the parentheses first.\(\frac{5}{13}+(\frac{4}{4})\)
    Simplify the fraction.\(\frac{5}{13}+1\)
    Add.\(1\frac{5}{13}\)
    Convert to an improper fraction.\(\frac{18}{13}\)

  26. Simplify: \((\frac{7}{15}+\frac{5}{8})+\frac{3}{8}.\)

    جواب کھوليں

    \(\frac{22}{15}\)

  27. Simplify: \((\frac{2}{9}+\frac{7}{12})+\frac{5}{12}.\)

    جواب کھوليں

    \(\frac{11}{9}\)

  28. Simplify: \((6.47q+9.99q)+1.01q.\)

    جواب کھوليں

    Notice that the sum of the second and third coefficients is a whole number.

    \((6.47q+9.99q)+1.01q\)
    Change the grouping.\(6.47q+(9.99q+1.01q)\)
    Add in the parentheses first.\(6.47q+(11.00q)\)
    Add.\(17.47q\)

    Many people have good number sense when they deal with money. Think about adding \(99\) cents and \(1\) cent. Do you see how this applies to adding \(9.99+1.01?\)

  29. Simplify: \((5.58c+8.75c)+1.25c.\)

    جواب کھوليں

    15.58c

  30. Simplify: \((8.79d+3.55d)+5.45d.\)

    جواب کھوليں

    17.79d

  31. Simplify the expression: \([1.67(8)](0.25).\)

    جواب کھوليں

    Notice that multiplying \((8)(0.25)\) is easier than multiplying \(1.67(8)\) because it gives a whole number. (Think about having \(8\) quarters—that makes \(\text{\$2.)}\)

    \([1.67(8)](0.25)\)
    Regroup.\(1.67[(8)(0.25)]\)
    Multiply in the brackets first.\(1.67[2]\)
    Multiply.\(3.34\)

  32. Simplify: \([1.17(4)](2.25).\)

    جواب کھوليں

    10.53

  33. Simplify: \([3.52(8)](2.5).\)

    جواب کھوليں

    70.4

  34. Simplify: \(6(9x).\)

    جواب کھوليں
    \(6(9x)\)
    Use the associative property of multiplication to re-group.\((6\cdot 9)x\)
    Multiply in the parentheses.\(54x\)

  35. Simplify: \(8(3y).\)

    جواب کھوليں

    24y

  36. Simplify: \(12(5z).\)

    جواب کھوليں

    60z

  37. Simplify: \(18p+6q+(-15p)+5q.\)

    جواب کھوليں

    Use the Commutative Property of Addition to re-order so that like terms are together.

    \(18p+6q+(-15p)+5q\)
    Re-order terms.\(18p+(-15p)+6q+5q\)
    Combine like terms.\(3p+11q\)

  38. Simplify: \(23r+14s+9r+(-15s).\)

    جواب کھوليں

    32r − s

  39. Simplify: \(37m+21n+4m+(-15n).\)

    جواب کھوليں

    41m + 6n

  40. \(8(-12)=___\)

Symbols used here

\neq
not equal
The two sides are different.
\pm
plus or minus
Both signs at once: x = 3 ± 2 means 5 and 1.
\leq,\ \geq
less/greater than or equal
Inequalities that allow equality; < and > exclude it.
\approx
approximately equal
Equal to the precision shown, not exactly.
\sqrt{x},\ \sqrt[n]{x}
square root, n-th root
The non-negative number whose square (n-th power) is x.
a \bmod n
remainder
What is left after dividing a by n.
\%
per cent
Per hundred: 15% = 15/100.
a : b,\ \frac{a}{b}
ratio, fraction
a for every b; a divided by b.

How to: Commutative and Associative Properties

  1. Use the commutative and associative properties
  2. Evaluate expressions using the commutative and associative properties
  3. Simplify expressions using the commutative and associative properties

Questions people ask

Why does the order of operations matter?

Because 2 + 3 × 4 would otherwise be two different numbers. The convention (brackets, exponents, multiplication and division, addition and subtraction) exists so every reader gets the same value from the same expression.

How do I check an arithmetic answer?

Estimate first (round every number and compute roughly), then compare. If the estimate and the exact answer disagree by more than a little, one of them is wrong. The solver shows every operation, so you can find which line went astray.

Why are fractions harder than decimals?

They are not harder, they are more exact: 1/3 is a precise number, 0.333 is an approximation. Fractions need a common denominator to add, which is the one extra step people trip on.

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Parts of this page are adapted from OpenStax Prealgebra 2e (CC BY-NC-SA 4.0). Condensed and re-explained here; errors are ours.

میں زیادہ Arithmetic

Order of operationsFractionsPercentagesPowers and roots