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Galois group

In Galois theory, a branch of abstract algebra, the Galois group of a certain type of field extension is a symmetry group characterizing how it extends the base field.

Galois group

In Galois theory, a branch of abstract algebra, the Galois group of a certain type of field extension is a symmetry group characterizing how it extends the base field. Each element of the Galois group is a transformation of the field extension which leaves each element of the base field fixed.

This connection between fields and groups, given by the fundamental theorem of Galois theory, allows for group-theoretic tools to be used on problems in field theory, such as describing the solutions to quintic polynomials. The study of field extensions and their relationship to the polynomials that give rise to them via Galois groups is called Galois theory, so named in honor of Évariste Galois who first discovered them.

Informal description

A field is a set, like the rational numbers \(\mathbb{Q}\) or the real numbers \(\mathbb{R}\), on which the four operations of addition, subtraction, multiplication, and division are defined and have certain standardized properties. Fields can be extended into larger fields with the same operations, such as how \(\mathbb{Q}\) can be extended to \(\mathbb{R}\) and \(\mathbb{R}\) can be extended to the complex numbers \(\mathbb{C}\). These extensions may arise when there is no solution to a given equation within the smaller field (the base field) but there is in the extension: for instance, \(x^2 = 2\) has no solution in \(\mathbb{Q}\) but has two solutions in its extension \(\mathbb{R}\).

The problem of identifying and classifying the extensions of a field can be made easier by using group theory. Each extension of a field adds additional structure that is "invisible" to the base field, and the Galois group describes that structure. It does this by considering transformations which change the extension but leave the base field unchanged. For instance, the transformation of complex conjugation, which maps \(a + bi \mapsto a - bi\), leaves every real number fixed but generally does not leave complex numbers fixed. The "Galois group of \(\mathbb{C}\) over \(\mathbb{R}\)", written \(\text{Gal}(\mathbb{C}/\mathbb{R})\), is the cyclic group of order 2 (equivalently, the integers modulo 2), with its one non-identity element representing this transformation of complex conjugation.

Definition

Suppose that \(E\) is an extension of the field \(F\) (written as \(E/F\) and read "E over F"). An automorphism of \(E/F\) is defined to be an automorphism of \(E\) that fixes \(F\) pointwise. In other words, an automorphism of \(E/F\) is an isomorphism \(\alpha:E\to E\) such that \(\alpha(x) = x\) for each \(x\in F\). The set of all automorphisms of \(E/F\) forms a group with the operation of function composition. This group is sometimes denoted by \(\operatorname{Aut}(E/F).\)

If \(E/F\) is a Galois extension, then \(\operatorname{Aut}(E/F)\) is called the Galois group of \(E/F\), and is usually denoted by \(\operatorname{Gal}(E/F)\).

If \(E/F\) is not a Galois extension, then the Galois group of \(E/F\) is sometimes defined as \(\operatorname{Aut}(K/F)\), where \(K\) is the Galois closure of \(E\).

Galois group of a polynomial

Another definition of the Galois group comes from the Galois group of an irreducible polynomial \(f \in F[x]\). If there is a field \(K/F\) such that \(f\) factors as a product of distinct linear polynomials

\(f(x) = (x-\alpha_1)\cdots (x - \alpha_k) \in K[x]\)

over the field \(K\), then the Galois group of the polynomial \(f\) is defined as the Galois group of \(K/F\) where \(K\) is minimal among all such fields.

Fundamental theorem of Galois theory

One of the important structure theorems from Galois theory comes from the fundamental theorem of Galois theory. This states that given a finite Galois extension \(K/k\), there is a bijection between the set of subfields \(k \subset E \subset K\) and the subgroups \(H \subset G.\) Then, \(E\) is given by the set of invariants of \(K\) under the action of \(H\), so

\(E = K^H = \{ a\in K : \forall g \in H,\ ga = a \}\)

Moreover, if \(H\) is a normal subgroup then \(G/H \cong \operatorname{Gal}(E/k)\). And conversely, if \(E/k\) is a normal field extension, then the associated subgroup in \(\operatorname{Gal}(K/k)\) is a normal group.

Lattice structure

Suppose \(K_1,K_2\) are Galois extensions of \(k\) with Galois groups \(G_1,G_2.\) The field \(K_1K_2\) with Galois group \(G = \operatorname{Gal}(K_1K_2/k)\) has an injection \(G \to G_1 \times G_2\) which is an isomorphism whenever \(K_1 \cap K_2 = k\).

Examples

In the following examples \(F\) is a field, and \(\Complex, \R, \Q\) are the fields of complex, real, and rational numbers, respectively. The notation F(a) indicates the field extension obtained by adjoining an element a to the field F.

Trivial group

\(\operatorname{Gal}(F/F)\) is the trivial group that has a single element, namely the identity automorphism.

Another example of a Galois group which is trivial is \(\operatorname{Aut}(\R/\Q).\) Indeed, it can be shown that any automorphism of \(\R\) must preserve the ordering of the real numbers and hence must be the identity.

Consider the field \(K = \Q(\sqrt[3]{2}).\) The group \(\operatorname{Aut}(K/\Q)\) contains only the identity automorphism. This is because \(K\) is not a normal extension, since the other two cube roots of \(2\),

\({\exp} \bigl(\tfrac23 \pi i \bigr) \sqrt[3]{2},\quad {\exp} \bigl(\tfrac43 \pi i \bigr) \sqrt[3]{2},\)

are missing from the extension, in other words K is not a splitting field.

Finite non-abelian groups

Consider now \(L = \Q(\sqrt[3]{2}, \omega),\) where \(\omega\) is a primitive cube root of unity. The group \(\operatorname{Gal}(L/\Q)\) is isomorphic to S3, the dihedral group of order 6, and L is in fact the splitting field of \(x^3-2\) over \(\Q.\)

Comparing Galois groups of field extensions of global fields

Given a global field extension \(K/k\) (such as \(\mathbb{Q}(\sqrt[5]{3},\zeta_5 )/\mathbb{Q}\)) and equivalence classes of valuations \(w\) on \(K\) (such as the \(p\)-adic valuation) and \(v\) on \(k\) such that their completions give a Galois field extension

\(K_w/k_v\)

of local fields, there is an induced action of the Galois group \(G = \operatorname{Gal}(K/k)\) on the set of equivalence classes of valuations such that the completions of the fields are compatible. This means if \(s \in G\) then there is an induced isomorphism of local fields

\(s_w:K_w \to K_{sw}\)

Since we have taken the hypothesis that \(w\) lies over \(v\) (i.e. there is a Galois field extension \(K_w/k_v\)), the field morphism \(s_w\) is in fact an isomorphism of \(k_v\)-algebras. If we take the isotropy subgroup of \(G\) for the valuation class \(w\)

\(G_w = \{s \in G : sw = w \}\)

then there is a surjection of the global Galois group to the local Galois group such that there is an isomorphism between the local Galois group and the isotropy subgroup. Diagrammatically, this means

\(\begin{matrix} \operatorname{Gal}(K/v)& \twoheadrightarrow & \operatorname{Gal}(K_w/k_v) \\ \downarrow & & \downarrow \\ G & \twoheadrightarrow & G_w \end{matrix}\)

where the vertical arrows are isomorphisms. This gives a technique for constructing Galois groups of local fields using global Galois groups.

Infinite groups

A basic example of a field extension with an infinite group of automorphisms is \(\operatorname{Aut}(\Complex/\Q)\), since it contains every algebraic field extension \(E/\Q\). For example, the field extensions \(\Q(\sqrt{a})/\Q\) for a square-free element \(a \in \Q\) each have a unique degree \(2\) automorphism, inducing an automorphism in \(\operatorname{Aut}(\Complex/\Q).\)

One of the most studied classes of infinite Galois group is the absolute Galois group, which is an infinite, profinite group defined as the inverse limit of all finite Galois extensions \(E/F\) for a fixed field. The inverse limit is denoted

\(\operatorname{Gal}(\overline{F}/F) := \varprojlim_{E/F \text{ finite separable}}{\operatorname{Gal}(E/F)}\),

where \(\overline{F}\) is the separable closure of the field \(F\). Note this group is a topological group. Some basic examples include \(\operatorname{Gal}(\overline{\Q}/\Q)\) and

\(\operatorname{Gal}(\overline{\mathbb{F}}_q/\mathbb{F}_q) \cong \hat{\Z} \cong \prod_p \Z_p\).

Another readily computable example comes from the field extension \(\Q(\sqrt{2},\sqrt{3},\sqrt{5}, \ldots)/ \Q\) containing the square root of every positive prime. It has Galois group

\(\operatorname{Gal}(\Q(\sqrt{2},\sqrt{3},\sqrt{5}, \ldots)/ \Q) \cong \prod_{p} \Z/2\),

which can be deduced from the profinite limit

\(\cdots \to \operatorname{Gal}(\Q(\sqrt{2},\sqrt{3},\sqrt{5})/\Q) \to \operatorname{Gal}(\Q(\sqrt{2},\sqrt{3})/\Q) \to \operatorname{Gal}(\Q(\sqrt{2})/\Q)\)

and using the computation of the Galois groups.

Properties

The significance of an extension being Galois is that it obeys the fundamental theorem of Galois theory: the closed (with respect to the Krull topology) subgroups of the Galois group correspond to the intermediate fields of the field extension.

If \(E/F\) is a Galois extension, then \(\operatorname{Gal}(E/F)\) can be given a topology, called the Krull topology, that makes it into a profinite group.

Now you Ոչ մի հաշվիչ չի կարող լուծել այս խնդիրը, բայց դրա մասերը հաշվարկելի են։ Փորձեք ստորեւ նշվածներից մեկը կամ գրեք ձեր սեփականը։

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Տեղադրեք ցանկացած նշան՝ ամբողջական սահմանման, նկարի և դրա մեջ ամեն մի տառի իմաստը տեսնելու համար։

Հարցեր, որոնք մարդիկ տալիս են :

What is a group, in plain words?

A set with one operation that is associative, has an identity, and lets every element be undone. Symmetries of any object form a group. That is where the idea came from.

What is the difference between a ring and a field?

A ring has addition and multiplication that behave like the integers (you cannot always divide); a field is a ring where every non-zero element has a reciprocal, like the rationals or the reals.

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